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For your club's fundraiser, you decided to hold a bake sale. In order to make bakery items, you had to purchase 12 pounds of sugar and 15 pounds of flour. Your total cost was [tex]$\$[/tex]9.30[tex]$. On a second trip to the grocery store, you purchased 4 pounds of sugar and 10 pounds of flour for a total cost of $[/tex]\[tex]$4.60$[/tex]. Which of the following represents the system of equations for this problem?

A.
[tex]\[
\begin{array}{l}
12s + 4s = 9.30 \\
15f + 10f = 4.60 \\
12s + 15f = 9.30 \\
4s + 10f = 4.60
\end{array}
\][/tex]

B.
[tex]\[
12s + 15f = 9.30 \\
4s + 10f = 4.60
\][/tex]

C.
[tex]\[
\begin{array}{l}
12s + 15f = 4.60 \\
4s + 10f = 9.30 \\
12s + 15f = 9.30 \\
10s + 4f = 4.60
\end{array}
\][/tex]


Sagot :

To determine the appropriate system of equations for the given problem, let's break down the information provided and derive the equations step by step.

### Information Provided:
1. On your first trip to the grocery store, you purchased:
- 12 pounds of sugar
- 15 pounds of flour
- Total cost: \[tex]$9.30 2. On your second trip to the grocery store, you purchased: - 4 pounds of sugar - 10 pounds of flour - Total cost: \$[/tex]4.60

### Define Variables:
- Let [tex]\( s \)[/tex] represent the cost per pound of sugar.
- Let [tex]\( f \)[/tex] represent the cost per pound of flour.

### Create Equations:
1. For the first trip:
- The cost of 12 pounds of sugar: [tex]\( 12s \)[/tex]
- The cost of 15 pounds of flour: [tex]\( 15f \)[/tex]
- The total cost of the first trip: [tex]\( 12s + 15f = 9.30 \)[/tex]

2. For the second trip:
- The cost of 4 pounds of sugar: [tex]\( 4s \)[/tex]
- The cost of 10 pounds of flour: [tex]\( 10f \)[/tex]
- The total cost of the second trip: [tex]\( 4s + 10f = 4.60 \)[/tex]

### System of Equations:
Combining the above equations, we get the following system of equations:

[tex]\[ \begin{aligned} 1.\quad & 12s + 15f = 9.30 \\ 2.\quad & 4s + 10f = 4.60 \end{aligned} \][/tex]

So, the correct system of equations that represent this problem is:

[tex]\[ \begin{array}{l} 12s + 15f = 9.30 \\ 4s + 10f = 4.60 \end{array} \][/tex]

Among the provided options, matches the following:
- [tex]\( 12s + 15f = 9.30 \)[/tex]
- [tex]\( 4s + 10f = 4.60 \)[/tex]

These are represented correctly as:

[tex]\[ 12s + 15f = 9.30 \\ 4s + 10f = 4.60 \][/tex]

This is the correct answer.