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Sagot :
To solve the equation [tex]\(A^2 + B^2 = A^2 + X^2\)[/tex], we can follow these steps:
1. Subtract [tex]\(A^2\)[/tex] from both sides:
[tex]\[ A^2 + B^2 - A^2 = A^2 + X^2 - A^2 \][/tex]
Simplifying this, we get:
[tex]\[ B^2 = X^2 \][/tex]
2. Take the square root of both sides:
[tex]\[ \sqrt{B^2} = \sqrt{X^2} \][/tex]
Remembering that the square root of a square yields both a positive and a negative solution, we obtain:
[tex]\[ B = \pm X \][/tex]
Thus, the value of [tex]\(B\)[/tex] that satisfies the equation [tex]\(A^2 + B^2 = A^2 + X^2\)[/tex] is [tex]\(B = \pm X\)[/tex].
Therefore, the correct answer is:
a) [tex]\(\pm X\)[/tex]
1. Subtract [tex]\(A^2\)[/tex] from both sides:
[tex]\[ A^2 + B^2 - A^2 = A^2 + X^2 - A^2 \][/tex]
Simplifying this, we get:
[tex]\[ B^2 = X^2 \][/tex]
2. Take the square root of both sides:
[tex]\[ \sqrt{B^2} = \sqrt{X^2} \][/tex]
Remembering that the square root of a square yields both a positive and a negative solution, we obtain:
[tex]\[ B = \pm X \][/tex]
Thus, the value of [tex]\(B\)[/tex] that satisfies the equation [tex]\(A^2 + B^2 = A^2 + X^2\)[/tex] is [tex]\(B = \pm X\)[/tex].
Therefore, the correct answer is:
a) [tex]\(\pm X\)[/tex]
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