ValkyrieRidn
Answered

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A cashier counted the number of customers in their line every minute for 30 minutes.

\begin{tabular}{|l|l|l|l|l|l|l|l|}
\hline Customers & 0 & 1 & 2 & 3 & 4 & 5 & Total \\
\hline Frequency & 5 & 3 & 9 & 7 & 4 & 2 & 30 \\
\hline
\end{tabular}

Find the probability that there were exactly 2 customers in line.

[tex]\[ P(2) = \frac{\text{Frequency of } 2}{\text{Total Frequency}} \][/tex]
[tex]\[ P(2) = \frac{9}{30} \][/tex]

Sagot :

GinnyAnsweridn
To find the probability that there were exactly 2 customers in line, you can use the formula for probability:

[tex]\[ P(2) = \frac{\text{Frequency of 2 customers}}{\text{Total Frequency}} \][/tex]

Given the data:
- The frequency of exactly 2 customers is 9.
- The total frequency (or total number of observations) is 30.

Plugging these values into the formula:

[tex]\[ P(2) = \frac{9}{30} \][/tex]

To simplify this fraction, you divide both the numerator and the denominator by their greatest common divisor, which is 3:

[tex]\[ P(2) = \frac{9 \div 3}{30 \div 3} \][/tex]
[tex]\[ P(2) = \frac{3}{10} \][/tex]

Thus, the probability that there were exactly 2 customers in line is:

[tex]\[ P(2) = 0.3 \][/tex]

So, the probability of exactly 2 customers in line at any given minute is 0.3 or 30%.
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