IDNLearn.com: Your go-to resource for finding precise and accurate answers. Discover prompt and accurate answers from our experts, ensuring you get the information you need quickly.
Sagot :
To simplify the expression [tex]\( e^{8-4 \ln (x) + 3 \ln (y)} \)[/tex], we can apply some properties of logarithms and exponents. Here's a step-by-step solution:
1. Identify and Separate the Terms:
The expression inside the exponent is [tex]\( 8 - 4 \ln(x) + 3 \ln(y) \)[/tex].
2. Distribute the Exponentiation:
We can rewrite the expression inside the exponential function for easier handling:
[tex]\[ 8 - 4 \ln(x) + 3 \ln(y) \][/tex]
3. Exponentiation and Properties of Logarithms:
We know from properties of logarithms that [tex]\(\ln(a^b) = b \ln(a)\)[/tex]. We can use this property to separate the terms in the exponent.
4. Separate the Terms inside the Exponent:
By splitting the exponentiation of the sum:
[tex]\[ e^{8 - 4 \ln(x) + 3 \ln(y)} = e^8 \cdot e^{-4 \ln(x)} \cdot e^{3 \ln(y)} \][/tex]
5. Simplify Using [tex]\( e^{\ln(a)} = a \)[/tex]:
Apply the exponential and logarithmic properties:
[tex]\[ e^{-4 \ln(x)} = (e^{\ln(x)})^{-4} = x^{-4} \][/tex]
[tex]\[ e^{3 \ln(y)} = (e^{\ln(y)})^3 = y^3 \][/tex]
6. Combine the Expressions:
Putting it all together:
[tex]\[ e^{8 - 4 \ln(x) + 3 \ln(y)} = e^8 \cdot x^{-4} \cdot y^3 \][/tex]
7. Rewriting the Terms:
Combine the constants and appropriate terms to get the final expression:
[tex]\[ e^{8 - 4 \ln(x) + 3 \ln(y)} = \frac{y^3 \cdot e^8}{x^4} \][/tex]
Thus, the simplified form of the expression [tex]\( e^{8-4\ln(x)+3\ln(y)} \)[/tex] is:
[tex]\[ \boxed{\frac{y^3 e^8}{x^4}} \][/tex]
1. Identify and Separate the Terms:
The expression inside the exponent is [tex]\( 8 - 4 \ln(x) + 3 \ln(y) \)[/tex].
2. Distribute the Exponentiation:
We can rewrite the expression inside the exponential function for easier handling:
[tex]\[ 8 - 4 \ln(x) + 3 \ln(y) \][/tex]
3. Exponentiation and Properties of Logarithms:
We know from properties of logarithms that [tex]\(\ln(a^b) = b \ln(a)\)[/tex]. We can use this property to separate the terms in the exponent.
4. Separate the Terms inside the Exponent:
By splitting the exponentiation of the sum:
[tex]\[ e^{8 - 4 \ln(x) + 3 \ln(y)} = e^8 \cdot e^{-4 \ln(x)} \cdot e^{3 \ln(y)} \][/tex]
5. Simplify Using [tex]\( e^{\ln(a)} = a \)[/tex]:
Apply the exponential and logarithmic properties:
[tex]\[ e^{-4 \ln(x)} = (e^{\ln(x)})^{-4} = x^{-4} \][/tex]
[tex]\[ e^{3 \ln(y)} = (e^{\ln(y)})^3 = y^3 \][/tex]
6. Combine the Expressions:
Putting it all together:
[tex]\[ e^{8 - 4 \ln(x) + 3 \ln(y)} = e^8 \cdot x^{-4} \cdot y^3 \][/tex]
7. Rewriting the Terms:
Combine the constants and appropriate terms to get the final expression:
[tex]\[ e^{8 - 4 \ln(x) + 3 \ln(y)} = \frac{y^3 \cdot e^8}{x^4} \][/tex]
Thus, the simplified form of the expression [tex]\( e^{8-4\ln(x)+3\ln(y)} \)[/tex] is:
[tex]\[ \boxed{\frac{y^3 e^8}{x^4}} \][/tex]
We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Thanks for visiting IDNLearn.com. We’re dedicated to providing clear answers, so visit us again for more helpful information.