Discover new knowledge and insights with IDNLearn.com's extensive Q&A platform. Discover in-depth and trustworthy answers to all your questions from our experienced community members.

Ping lives at the corner of 3rd Street and 6th Avenue. Ari lives at the corner of 21st Street and 18th Avenue. There is a gym located [tex]$\frac{2}{3}$[/tex] of the distance from Ping's home to Ari's home.

[tex]\[
\begin{array}{l}
x=\left(\frac{m}{m+n}\right)\left(x_2-x_1\right)+x_1 \\
y=\left(\frac{m}{m+n}\right)\left(y_2-y_1\right)+y_1
\end{array}
\][/tex]

Where is the gym?

A. 9th Street and 10th Avenue

B. 12th Street and 12th Avenue

C. 14th Street and 12th Avenue

D. 15th Street and 14th Avenue


Sagot :

Sure, let's break down the problem step by step and determine the correct coordinates of the gym.

1. Identify Given Points:

- Ping's coordinates are [tex]\((3, 6)\)[/tex]:
[tex]\[ x_1 = 3, \quad y_1 = 6 \][/tex]
- Ari's coordinates are [tex]\((21, 18)\)[/tex]:
[tex]\[ x_2 = 21, \quad y_2 = 18 \][/tex]

2. Distance Ratio:
- The gym is [tex]\(\frac{2}{3}\)[/tex] of the distance from Ping's home to Ari's home.
- Let [tex]\(m = 2\)[/tex] and [tex]\(n = 3 - 2 = 1\)[/tex].

3. Apply the Formula for the Coordinates:
- The formula for finding a point that divides the line segment between [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex] in the ratio [tex]\(m:n\)[/tex] is:
[tex]\[ x = \left(\frac{m}{m+n}\right)(x_2 - x_1) + x_1 \][/tex]
[tex]\[ y = \left(\frac{m}{m+n}\right)(y_2 - y_1) + y_1 \][/tex]

- Plugging in the given values:
[tex]\[ x = \left(\frac{2}{2+1}\right)(21 - 3) + 3 \][/tex]
[tex]\[ x = \left(\frac{2}{3}\right) \times 18 + 3 \][/tex]
[tex]\[ x = 12 + 3 = 15 \][/tex]

Similarly for [tex]\(y\)[/tex]:
[tex]\[ y = \left(\frac{2}{2+1}\right)(18 - 6) + 6 \][/tex]
[tex]\[ y = \left(\frac{2}{3}\right) \times 12 + 6 \][/tex]
[tex]\[ y = 8 + 6 = 14 \][/tex]

4. Conclusion:
- The coordinates of the gym are [tex]\((15, 14)\)[/tex].

Hence, the gym is located at the corner of 15th Street and 14th Avenue.