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Sagot :
To determine which expression is equivalent to [tex]\((4 + 7i)(3 + 4i)\)[/tex], let's go through the multiplication of these two complex numbers step by step.
To multiply two complex numbers, we can use the distributive property (also known as the FOIL method for binomials):
[tex]\[ (4 + 7i)(3 + 4i) \][/tex]
Step 1: Distribute [tex]\(4\)[/tex] in the first term over the second complex number:
[tex]\[ 4 \cdot 3 + 4 \cdot 4i = 12 + 16i \][/tex]
Step 2: Distribute [tex]\(7i\)[/tex] in the first term over the second complex number:
[tex]\[ 7i \cdot 3 + 7i \cdot 4i = 21i + 28i^2 \][/tex]
Step 3: Combine the results:
[tex]\[ 12 + 16i + 21i + 28i^2 \][/tex]
Step 4: Recall that [tex]\(i^2 = -1\)[/tex], so substitute [tex]\(-1\)[/tex] in for [tex]\(i^2\)[/tex]:
[tex]\[ 12 + 16i + 21i + 28(-1) \][/tex]
Step 5: Simplify the expression:
[tex]\[ 12 + 16i + 21i - 28 \][/tex]
Step 6: Combine like terms (real parts together and imaginary parts together):
[tex]\[ (12 - 28) + (16i + 21i) = -16 + 37i \][/tex]
Therefore, the expression that is equivalent to [tex]\((4 + 7i)(3 + 4i)\)[/tex] is:
[tex]\[ -16 + 37i \][/tex]
So, the correct option is:
[tex]\[ -16 + 37i \][/tex]
To multiply two complex numbers, we can use the distributive property (also known as the FOIL method for binomials):
[tex]\[ (4 + 7i)(3 + 4i) \][/tex]
Step 1: Distribute [tex]\(4\)[/tex] in the first term over the second complex number:
[tex]\[ 4 \cdot 3 + 4 \cdot 4i = 12 + 16i \][/tex]
Step 2: Distribute [tex]\(7i\)[/tex] in the first term over the second complex number:
[tex]\[ 7i \cdot 3 + 7i \cdot 4i = 21i + 28i^2 \][/tex]
Step 3: Combine the results:
[tex]\[ 12 + 16i + 21i + 28i^2 \][/tex]
Step 4: Recall that [tex]\(i^2 = -1\)[/tex], so substitute [tex]\(-1\)[/tex] in for [tex]\(i^2\)[/tex]:
[tex]\[ 12 + 16i + 21i + 28(-1) \][/tex]
Step 5: Simplify the expression:
[tex]\[ 12 + 16i + 21i - 28 \][/tex]
Step 6: Combine like terms (real parts together and imaginary parts together):
[tex]\[ (12 - 28) + (16i + 21i) = -16 + 37i \][/tex]
Therefore, the expression that is equivalent to [tex]\((4 + 7i)(3 + 4i)\)[/tex] is:
[tex]\[ -16 + 37i \][/tex]
So, the correct option is:
[tex]\[ -16 + 37i \][/tex]
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