To determine if Robert meets at least 75% of his recommended daily allowance for vitamins B12, C, and E, let's first calculate the total intake of each vitamin from his meal.
From the given nutrient values:
- Salmon fillet (124 g):
- Vitamin B12: [tex]\(5.87 \mu g\)[/tex]
- Vitamin C: [tex]\(0.0 mg\)[/tex]
- Vitamin E: [tex]\(0.60 mg\)[/tex]
- Boiled green beans (1 cup):
- Vitamin B12: [tex]\(0.0 \mu g\)[/tex]
- Vitamin C: [tex]\(12.1 mg\)[/tex]
- Vitamin E: [tex]\(0.57 mg\)[/tex]
- Strawberries, sliced (1/2 cup):
- Vitamin B12: [tex]\(0.0 \mu g\)[/tex]
- Vitamin C: [tex]\(49.0 mg\)[/tex]
- Vitamin E: [tex]\(0.42 mg\)[/tex]
Adding these amounts together, we get the total intake for each vitamin:
- Total Vitamin B12:
[tex]\[5.87 \mu g + 0.0 \mu g + 0.0 \mu g = 5.87 \mu g\][/tex]
- Total Vitamin C:
[tex]\[0.0 mg + 12.1 mg + 49.0 mg = 61.1 mg\][/tex]
- Total Vitamin E:
[tex]\[0.60 mg + 0.57 mg + 0.42 mg = 1.59 mg\][/tex]
Now, we need to compare these values to 75% of the recommended daily allowance for each vitamin.
- Recommended dietary intake:
- Vitamin B12: [tex]\(2.4 \mu g/day\)[/tex]
- Vitamin C: [tex]\(75 mg/day\)[/tex]
- Vitamin E: [tex]\(15 mg/day\)[/tex]
- 75% of the recommended daily intake:
[tex]\[0.75 \times 2.4 \mu g = 1.8 \mu g\][/tex]
[tex]\[0.75 \times 75 mg = 56.25 mg\][/tex]
[tex]\[0.75 \times 15 mg = 11.25 mg\][/tex]
Comparison with 75% of recommended intake:
- Vitamin B12:
[tex]\[5.87 \mu g \geq 1.8 \mu g\][/tex]
--> (Meets 75% requirement)
- Vitamin C:
[tex]\[61.1 mg \geq 56.25 mg\][/tex]
--> (Meets 75% requirement)
- Vitamin E:
[tex]\[1.59 mg < 11.25 mg\][/tex]
--> (Does NOT meet 75% requirement)
Thus, Robert meets at least 75% of his recommended daily allowance for Vitamin B12 and Vitamin C, but not for Vitamin E.
Therefore, the correct answer is:
B. vitamin B12 and vitamin C only.
