Get personalized answers to your unique questions on IDNLearn.com. Ask any question and get a detailed, reliable answer from our community of experts.
Sagot :
Answer:
8.21 m/s²
Note: This answer was rounded to three significant figures.
Explanation:
To determine the value of the gravitational acceleration (g) at the astronaut's location, we will use the relationship between weight and gravitational force.
[tex]\boxed{ \begin{array}{ccc} \text{\underline{Weight of an Object:}} \\\\ \vec w = mg \\\\ \text{Where:} \\ \bullet \ \vec w \ \text{is the weight of the object (force due to gravity)} \\ \bullet \ m \ \text{is the mass of the object} \\ \bullet \ g \ \text{is the acceleration due to gravity} \end{array} }[/tex]
We are given:
- m = 80.0 kg
- w = 657 N
We want to solve for 'g' using the above equation:
[tex]\Longrightarrow 657 \text{ N}=(80.0 \text{ kg})g[/tex]
[tex]\Longrightarrow g=\dfrac{657 \text{ N}}{80.0 \text{ kg}}[/tex]
[tex]\therefore g \approx \boxed{8.21 \text{m/s}^2}[/tex]
Thus, the value of 'g' at the astronaut's location is approximately 8.21 m/s².
We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Your questions deserve reliable answers. Thanks for visiting IDNLearn.com, and see you again soon for more helpful information.