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Sagot :
Sure, let's solve the equation [tex]\(3^{2x} = \frac{1}{81}\)[/tex] step-by-step.
1. Understand the components of the equation:
- We have an exponential equation where the base is [tex]\(3\)[/tex].
2. Rewrite [tex]\(\frac{1}{81}\)[/tex] in terms of base 3:
- Notice that [tex]\(81 = 3^4\)[/tex]. Hence, [tex]\(\frac{1}{81} = \frac{1}{3^4} = 3^{-4}\)[/tex].
Now the equation becomes:
[tex]\[ 3^{2x} = 3^{-4} \][/tex]
3. Set the exponents equal to each other:
- Since the bases are the same, we can equate the exponents:
[tex]\[ 2x = -4 \][/tex]
4. Solve for [tex]\(x\)[/tex]:
- Divide both sides of the equation by 2 to isolate [tex]\(x\)[/tex]:
[tex]\[ x = \frac{-4}{2} \][/tex]
[tex]\[ x = -2 \][/tex]
So, the solution to the equation [tex]\(3^{2x} = \frac{1}{81}\)[/tex] is:
[tex]\[ x = -2 \][/tex]
1. Understand the components of the equation:
- We have an exponential equation where the base is [tex]\(3\)[/tex].
2. Rewrite [tex]\(\frac{1}{81}\)[/tex] in terms of base 3:
- Notice that [tex]\(81 = 3^4\)[/tex]. Hence, [tex]\(\frac{1}{81} = \frac{1}{3^4} = 3^{-4}\)[/tex].
Now the equation becomes:
[tex]\[ 3^{2x} = 3^{-4} \][/tex]
3. Set the exponents equal to each other:
- Since the bases are the same, we can equate the exponents:
[tex]\[ 2x = -4 \][/tex]
4. Solve for [tex]\(x\)[/tex]:
- Divide both sides of the equation by 2 to isolate [tex]\(x\)[/tex]:
[tex]\[ x = \frac{-4}{2} \][/tex]
[tex]\[ x = -2 \][/tex]
So, the solution to the equation [tex]\(3^{2x} = \frac{1}{81}\)[/tex] is:
[tex]\[ x = -2 \][/tex]
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