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Find the distance [tex]s[/tex] covered by a point moving with linear velocity [tex]v[/tex] for a time [tex]t[/tex] if:

[tex]v = 16 \text{ feet/second}[/tex] and [tex]t = 5 \text{ seconds}[/tex]

[tex]s = \square \text{ feet}[/tex]

Sagot :

GinnyAnsweridn
Certainly, let's solve this step-by-step.

To find the distance [tex]\( s \)[/tex] covered by a point moving with a constant linear velocity [tex]\( v \)[/tex] over a period of time [tex]\( t \)[/tex], we can use the basic formula of motion in the context of constant velocity:

[tex]\[ s = v \times t \][/tex]

Here,
- [tex]\( v \)[/tex] is the velocity, given as 16 feet per second,
- [tex]\( t \)[/tex] is the time, given as 5 seconds.

Substituting the given values into the formula:

[tex]\[ s = 16 \, \text{feet/second} \times 5 \, \text{seconds} \][/tex]

[tex]\[ s = 80 \, \text{feet} \][/tex]

So, the distance [tex]\( s \)[/tex] covered by the point is:

[tex]\[ s = 80 \, \text{feet} \][/tex]
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