IDNLearn.com is designed to help you find reliable answers quickly and easily. Get prompt and accurate answers to your questions from our community of knowledgeable experts.
Sagot :
To solve this problem, we need to calculate the total momentum of the bus and the car after the collision. Here are the steps to find the solution:
1. Understand momentum: Momentum (p) is the product of mass (m) and velocity (v), given by the formula [tex]\( p = m \cdot v \)[/tex].
2. Calculate the momentum of the bus:
- Mass of the bus ([tex]\(m_{\text{bus}}\)[/tex]): [tex]\( 1.5 \times 10^3 \)[/tex] kg
- Velocity of the bus ([tex]\(v_{\text{bus}}\)[/tex]): [tex]\( +20 \)[/tex] m/s
- Momentum of the bus ([tex]\(p_{\text{bus}}\)[/tex]): [tex]\( p_{\text{bus}} = m_{\text{bus}} \cdot v_{\text{bus}} = 1.5 \times 10^3 \, \text{kg} \times 20 \, \text{m/s} = 30,000 \, \text{kg} \cdot \text{m/s} \)[/tex]
3. Calculate the momentum of the car:
- Mass of the car ([tex]\(m_{\text{car}}\)[/tex]): [tex]\( 9.5 \times 10^2 \)[/tex] kg
- Velocity of the car ([tex]\(v_{\text{car}}\)[/tex]): [tex]\( -26 \)[/tex] m/s
- Momentum of the car ([tex]\(p_{\text{car}}\)[/tex]): [tex]\( p_{\text{car}} = m_{\text{car}} \cdot v_{\text{car}} = 9.5 \times 10^2 \, \text{kg} \times (-26) \, \text{m/s} = -24,700 \, \text{kg} \cdot \text{m/s} \)[/tex]
4. Calculate the total momentum after the collision:
- Total momentum after the collision ([tex]\(p_{\text{total}}\)[/tex]): [tex]\( p_{\text{total}} = p_{\text{bus}} + p_{\text{car}} = 30,000 \, \text{kg} \cdot \text{m/s} + (-24,700 \, \text{kg} \cdot \text{m/s}) = 5,300 \, \text{kg} \cdot \text{m/s} \)[/tex]
The total momentum after the collision is [tex]\( 5,300 \, \text{kg} \cdot \text{m/s} \)[/tex], which corresponds to option C.
So, the correct answer is:
C. [tex]\( 5.3 \times 10^3 \)[/tex] kilogram meters/second
1. Understand momentum: Momentum (p) is the product of mass (m) and velocity (v), given by the formula [tex]\( p = m \cdot v \)[/tex].
2. Calculate the momentum of the bus:
- Mass of the bus ([tex]\(m_{\text{bus}}\)[/tex]): [tex]\( 1.5 \times 10^3 \)[/tex] kg
- Velocity of the bus ([tex]\(v_{\text{bus}}\)[/tex]): [tex]\( +20 \)[/tex] m/s
- Momentum of the bus ([tex]\(p_{\text{bus}}\)[/tex]): [tex]\( p_{\text{bus}} = m_{\text{bus}} \cdot v_{\text{bus}} = 1.5 \times 10^3 \, \text{kg} \times 20 \, \text{m/s} = 30,000 \, \text{kg} \cdot \text{m/s} \)[/tex]
3. Calculate the momentum of the car:
- Mass of the car ([tex]\(m_{\text{car}}\)[/tex]): [tex]\( 9.5 \times 10^2 \)[/tex] kg
- Velocity of the car ([tex]\(v_{\text{car}}\)[/tex]): [tex]\( -26 \)[/tex] m/s
- Momentum of the car ([tex]\(p_{\text{car}}\)[/tex]): [tex]\( p_{\text{car}} = m_{\text{car}} \cdot v_{\text{car}} = 9.5 \times 10^2 \, \text{kg} \times (-26) \, \text{m/s} = -24,700 \, \text{kg} \cdot \text{m/s} \)[/tex]
4. Calculate the total momentum after the collision:
- Total momentum after the collision ([tex]\(p_{\text{total}}\)[/tex]): [tex]\( p_{\text{total}} = p_{\text{bus}} + p_{\text{car}} = 30,000 \, \text{kg} \cdot \text{m/s} + (-24,700 \, \text{kg} \cdot \text{m/s}) = 5,300 \, \text{kg} \cdot \text{m/s} \)[/tex]
The total momentum after the collision is [tex]\( 5,300 \, \text{kg} \cdot \text{m/s} \)[/tex], which corresponds to option C.
So, the correct answer is:
C. [tex]\( 5.3 \times 10^3 \)[/tex] kilogram meters/second
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. For dependable and accurate answers, visit IDNLearn.com. Thanks for visiting, and see you next time for more helpful information.