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Sagot :
To determine if the program correctly prints the sequence "10987654321", let's delve into the step-by-step logic of how such a sequence could be generated.
1. Initialize an empty string to store the countdown sequence:
- We start with an empty string: `countdown = ''`.
2. Run a loop to concatenate the numbers from 10 to 1 in descending order:
- We use a loop to iterate over the numbers from 10 to 1:
```
for number in range(10, 0, -1):
countdown += str(number)
```
- This loop will concatenate each number to the `countdown` string:
- After `number = 10`, the string becomes: `countdown = '10'`
- After `number = 9`, the string becomes: `countdown = '109'`
- After `number = 8`, the string becomes: `countdown = '1098'`
- After `number = 7`, the string becomes: `countdown = '10987'`
- Continue this process until `number = 1`, the string becomes: `countdown = '10987654321'`
3. Compare the generated sequence with the expected sequence:
- The final concatenation result stored in `countdown` should be "10987654321".
4. Determine if the condition for the output is met:
- Compare the generated string with "10987654321":
```
output = countdown + '1'
```
- We realize an additional '1' appended to `countdown` makes the string `countdown = '109876543211'`.
- We then check for equality:
```
return '109876543211' == '10987654321'
```
- This comparison should return `False` since the appended '1' causes the strings to be unequal.
5. Conclusion:
- Because we appended an incorrect '1' at the end of our countdown string before final comparison, causing a mismatch, the output evaluation result is `False`.
Thus, for the question:
Assuming the following block of code is embedded in an otherwise "working" program, the output of the program will print "10987654321".
The correct answer is:
False
1. Initialize an empty string to store the countdown sequence:
- We start with an empty string: `countdown = ''`.
2. Run a loop to concatenate the numbers from 10 to 1 in descending order:
- We use a loop to iterate over the numbers from 10 to 1:
```
for number in range(10, 0, -1):
countdown += str(number)
```
- This loop will concatenate each number to the `countdown` string:
- After `number = 10`, the string becomes: `countdown = '10'`
- After `number = 9`, the string becomes: `countdown = '109'`
- After `number = 8`, the string becomes: `countdown = '1098'`
- After `number = 7`, the string becomes: `countdown = '10987'`
- Continue this process until `number = 1`, the string becomes: `countdown = '10987654321'`
3. Compare the generated sequence with the expected sequence:
- The final concatenation result stored in `countdown` should be "10987654321".
4. Determine if the condition for the output is met:
- Compare the generated string with "10987654321":
```
output = countdown + '1'
```
- We realize an additional '1' appended to `countdown` makes the string `countdown = '109876543211'`.
- We then check for equality:
```
return '109876543211' == '10987654321'
```
- This comparison should return `False` since the appended '1' causes the strings to be unequal.
5. Conclusion:
- Because we appended an incorrect '1' at the end of our countdown string before final comparison, causing a mismatch, the output evaluation result is `False`.
Thus, for the question:
Assuming the following block of code is embedded in an otherwise "working" program, the output of the program will print "10987654321".
The correct answer is:
False
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