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Determine the number of x-intercepts for the quadratic function:

[tex]\[ y = 3x^2 - 8x + 8 \][/tex]

A. 2
B. 1
C. 0


Sagot :

Certainly! To find the number of solutions (roots) for the quadratic equation [tex]\(y = 3x^2 - 8x + 8\)[/tex], we need to analyze its discriminant. A quadratic equation [tex]\(ax^2 + bx + c = 0\)[/tex] has a discriminant given by the formula:

[tex]\[ D = b^2 - 4ac \][/tex]

For the equation given:
[tex]\[ 3x^2 - 8x + 8 = 0 \][/tex]

we identify the coefficients:
[tex]\[ a = 3, \quad b = -8, \quad c = 8 \][/tex]

Now we substitute these values into the discriminant formula:

[tex]\[ D = (-8)^2 - 4 \cdot 3 \cdot 8 \][/tex]

Simplifying this:

[tex]\[ D = 64 - 96 \][/tex]

[tex]\[ D = -32 \][/tex]

The value of the discriminant [tex]\(D\)[/tex] is [tex]\(-32\)[/tex]. The discriminant tells us about the nature and number of roots of the quadratic equation:

- If [tex]\(D > 0\)[/tex], there are 2 distinct real roots.
- If [tex]\(D = 0\)[/tex], there is exactly 1 real root (a repeated root).
- If [tex]\(D < 0\)[/tex], there are no real roots, only complex roots.

Since [tex]\(D = -32\)[/tex] is less than zero, this means that the quadratic equation [tex]\(3x^2 - 8x + 8 = 0\)[/tex] has no real roots.

Therefore, the number of real solutions for the equation [tex]\(y = 3x^2 - 8x + 8\)[/tex] is:

[tex]\[ \boxed{0} \][/tex]