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Given the partial pressure of methanol ([tex]\(CH_3OH\)[/tex]) is [tex]\(107.0 \, \text{mmHg}\)[/tex], calculate the mole fraction of methanol in the solution.

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If the question is not related to calculations and just presenting data, it can be formatted as:

The partial pressure of methanol ([tex]\(CH_3OH\)[/tex]) is [tex]\(107.0 \, \text{mmHg}\)[/tex].

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GinnyAnsweridn
Certainly! Let's go through the solution step-by-step for this question.

Given:
[tex]\[ PCH_3OH = 107.0 \text{ mmHg} \][/tex]

To solve this question:

1. We need to identify that [tex]\( PCH_3OH \)[/tex] is the vapor pressure of methanol ([tex]\( CH_3OH \)[/tex]) at a certain temperature.
2. The problem states that the vapor pressure of methanol at this specific condition is [tex]\( 107.0 \text{ mmHg} \)[/tex].
3. Since we are directly given the vapor pressure value, we can conclude that the vapor pressure of methanol, [tex]\( PCH_3OH \)[/tex], is [tex]\( 107.0 \text{ mmHg} \)[/tex].

So, the answer to the problem, in this context, is simply:

[tex]\[ \boxed{107.0 \text{ mmHg}} \][/tex]

This tells us that under the conditions specified in the question, the vapor pressure of methanol ([tex]\( CH_3OH \)[/tex]) is [tex]\( 107.0 \text{ mmHg} \)[/tex].
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