Answered

Explore a wide range of topics and get answers from experts on IDNLearn.com. Discover the information you need from our experienced professionals who provide accurate and reliable answers to all your questions.

Select the correct answer.

Brown eye color [tex]$(B)$[/tex] is dominant and blue eye color [tex]$(b)$[/tex] is recessive. In one school, 128 students have brown eyes and 72 students have blue eyes [tex]$(bb)$[/tex]. Which of the following correctly represents the possible frequencies of each genotype?

[tex]\[
p + q = 1, \quad p^2 + 2pq + q^2 = 1
\][/tex]

A. [tex]\( p^2 = 0.16, \, 2pq = 0.48, \, q^2 = 0.36 \)[/tex]

B. [tex]\( p^2 = 0.65, \, 2pq = 0.302, \, q^2 = 0.048 \)[/tex]

C. [tex]\( p^2 = 0.24, \, 2pq = 0.34, \, q^2 = 0.42 \)[/tex]

Sagot :

GinnyAnsweridn
To solve this problem, let's consider the Hardy-Weinberg principle which states that in a genetic equilibrium, the genotype frequencies in a population can be expressed as:
[tex]\[ p^2 + 2pq + q^2 = 1 \][/tex]
where:
- [tex]\( p \)[/tex] is the frequency of the dominant allele (B)
- [tex]\( q \)[/tex] is the frequency of the recessive allele (b)
- [tex]\( p^2 \)[/tex] is the frequency of the homozygous dominant genotype (BB)
- [tex]\( 2pq \)[/tex] is the frequency of the heterozygous genotype (Bb)
- [tex]\( q^2 \)[/tex] is the frequency of the homozygous recessive genotype (bb)

Given 128 students with brown eyes (BB or Bb) and 72 students with blue eyes (bb), let's determine the correct genotype frequencies.

1. Calculate the total number of students:
[tex]\[ 128 + 72 = 200 \][/tex]

2. Determine the frequency of the recessive phenotype (bb), which is [tex]\( q^2 \)[/tex]:
[tex]\[ q^2 = \frac{\text{number of students with blue eyes}}{\text{total number of students}} \][/tex]
[tex]\[ q^2 = \frac{72}{200} \][/tex]
[tex]\[ q^2 = 0.36 \][/tex]

3. Find [tex]\( q \)[/tex] (frequency of recessive allele):
[tex]\[ q = \sqrt{q^2} \][/tex]
[tex]\[ q = \sqrt{0.36} \][/tex]
[tex]\[ q = 0.6 \][/tex]

4. Calculate [tex]\( p \)[/tex] (frequency of the dominant allele):
[tex]\[ p = 1 - q \][/tex]
[tex]\[ p = 1 - 0.6 \][/tex]
[tex]\[ p = 0.4 \][/tex]

5. Determine the frequencies of the genotypes [tex]\( p^2 \)[/tex] (BB), [tex]\( 2pq \)[/tex] (Bb), and [tex]\( q^2 \)[/tex] (bb):
[tex]\[ p^2 = (0.4)^2 \][/tex]
[tex]\[ p^2 = 0.16 \][/tex]

[tex]\[ 2pq = 2 \cdot 0.4 \cdot 0.6 \][/tex]
[tex]\[ 2pq = 0.48 \][/tex]

[tex]\[ q^2 = 0.36 \][/tex] (already calculated)

Now, we compare these frequencies with the given options:

A. [tex]\( p^2 = 0.16, 2pq = 0.48, q^2 = 0.36 \)[/tex]
B. [tex]\( p^2 = 0.65, 2pq = 0.302, q^2 = 0.048 \)[/tex]
C. [tex]\( p^2 = 0.24, 2pq = 0.34, q^2 = 0.42 \)[/tex]

Given our calculated values, the correct frequencies are:
[tex]\[ \boxed{(0.16, 0.48, 0.36)} \][/tex]

Thus, the correct answer is:
A. [tex]\( p^2 = 0.16, 2pq = 0.48, q^2 = 0.36 \)[/tex]
We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Find the answers you need at IDNLearn.com. Thanks for stopping by, and come back soon for more valuable insights.