Get expert advice and community support for all your questions on IDNLearn.com. Get the information you need from our community of experts, who provide detailed and trustworthy answers.
Sagot :
Certainly! Let's solve this step by step.
To determine the maximum height reached by the golf ball, we start with the given relationship:
[tex]\[ h \text{ is proportional to } v^2 \][/tex]
This can be written mathematically as:
[tex]\[ h = k \cdot v^2 \][/tex]
where [tex]\( k \)[/tex] is the proportionality constant.
First, we need to determine the value of [tex]\( k \)[/tex] using the initial information provided:
[tex]\[ v = 20 \, \text{m/s}, \, h = 8 \, \text{m} \][/tex]
Substituting these values into the equation:
[tex]\[ 8 = k \cdot (20)^2 \][/tex]
[tex]\[ 8 = k \cdot 400 \][/tex]
Solving for [tex]\( k \)[/tex]:
[tex]\[ k = \frac{8}{400} \][/tex]
[tex]\[ k = 0.02 \][/tex]
Now that we have found the proportionality constant [tex]\( k \)[/tex], we can use it to find the maximum height [tex]\( h \)[/tex] when the speed [tex]\( v \)[/tex] is 35 m/s:
[tex]\[ v = 35 \, \text{m/s} \][/tex]
Using our equation again:
[tex]\[ h = k \cdot v^2 \][/tex]
Substituting [tex]\( k \)[/tex] and [tex]\( v \)[/tex]:
[tex]\[ h = 0.02 \cdot (35)^2 \][/tex]
[tex]\[ h = 0.02 \cdot 1225 \][/tex]
[tex]\[ h = 24.5 \, \text{m} \][/tex]
Therefore, the maximum height reached by the golf ball when its speed is 35 m/s is 24.5 meters.
To determine the maximum height reached by the golf ball, we start with the given relationship:
[tex]\[ h \text{ is proportional to } v^2 \][/tex]
This can be written mathematically as:
[tex]\[ h = k \cdot v^2 \][/tex]
where [tex]\( k \)[/tex] is the proportionality constant.
First, we need to determine the value of [tex]\( k \)[/tex] using the initial information provided:
[tex]\[ v = 20 \, \text{m/s}, \, h = 8 \, \text{m} \][/tex]
Substituting these values into the equation:
[tex]\[ 8 = k \cdot (20)^2 \][/tex]
[tex]\[ 8 = k \cdot 400 \][/tex]
Solving for [tex]\( k \)[/tex]:
[tex]\[ k = \frac{8}{400} \][/tex]
[tex]\[ k = 0.02 \][/tex]
Now that we have found the proportionality constant [tex]\( k \)[/tex], we can use it to find the maximum height [tex]\( h \)[/tex] when the speed [tex]\( v \)[/tex] is 35 m/s:
[tex]\[ v = 35 \, \text{m/s} \][/tex]
Using our equation again:
[tex]\[ h = k \cdot v^2 \][/tex]
Substituting [tex]\( k \)[/tex] and [tex]\( v \)[/tex]:
[tex]\[ h = 0.02 \cdot (35)^2 \][/tex]
[tex]\[ h = 0.02 \cdot 1225 \][/tex]
[tex]\[ h = 24.5 \, \text{m} \][/tex]
Therefore, the maximum height reached by the golf ball when its speed is 35 m/s is 24.5 meters.
Thank you for contributing to our discussion. Don't forget to check back for new answers. Keep asking, answering, and sharing useful information. Your questions find answers at IDNLearn.com. Thanks for visiting, and come back for more accurate and reliable solutions.