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Sagot :
Let's solve this problem using Ohm's Law, which relates voltage (V), current (I), and resistance (R). Ohm's Law is given by the formula:
[tex]\[ I = \frac{V}{R} \][/tex]
where:
- [tex]\( I \)[/tex] is the current in amperes (A),
- [tex]\( V \)[/tex] is the voltage in volts (V),
- [tex]\( R \)[/tex] is the resistance in ohms (Ω).
Given:
- The voltage [tex]\( V \)[/tex] is 120 volts,
- The resistance [tex]\( R \)[/tex] is 10 ohms.
To find the current [tex]\( I \)[/tex], we can substitute the given values into the Ohm's Law formula.
[tex]\[ I = \frac{120 \text{ volts}}{10 \text{ ohms}} \][/tex]
Now, perform the division:
[tex]\[ I = 12 \text{ amperes} \][/tex]
Therefore, the current flowing through the wire is 12 amperes.
[tex]\[ I = \frac{V}{R} \][/tex]
where:
- [tex]\( I \)[/tex] is the current in amperes (A),
- [tex]\( V \)[/tex] is the voltage in volts (V),
- [tex]\( R \)[/tex] is the resistance in ohms (Ω).
Given:
- The voltage [tex]\( V \)[/tex] is 120 volts,
- The resistance [tex]\( R \)[/tex] is 10 ohms.
To find the current [tex]\( I \)[/tex], we can substitute the given values into the Ohm's Law formula.
[tex]\[ I = \frac{120 \text{ volts}}{10 \text{ ohms}} \][/tex]
Now, perform the division:
[tex]\[ I = 12 \text{ amperes} \][/tex]
Therefore, the current flowing through the wire is 12 amperes.
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