Get the most out of your questions with the extensive resources available on IDNLearn.com. Our community is here to provide the comprehensive and accurate answers you need to make informed decisions.

What is the first step in writing [tex]f(x)=3x^2+6x-8[/tex] in vertex form?

A. Factor out 3 from each term.
B. Form a perfect square trinomial by keeping the value of the function equivalent.
C. Write the trinomial as a binomial squared.
D. Factor out 3 from the first two terms.


Sagot :

To begin writing the function [tex]\( f(x) = 3x^2 + 6x - 8 \)[/tex] in vertex form, we can start by factoring out 3 from the first two terms. Here's the first step, detailed step-by-step:

1. Identify the terms for factoring out: The quadratic term [tex]\( 3x^2 \)[/tex] and the linear term [tex]\( 6x \)[/tex].

2. Factor out the greatest common factor (GCF) from these terms: The GCF of [tex]\( 3x^2 \)[/tex] and [tex]\( 6x \)[/tex] is 3.

3. Rewrite the expression with 3 factored out:
[tex]\[ f(x) = 3x^2 + 6x - 8 \][/tex]
When we factor out 3 from the terms [tex]\( 3x^2 \)[/tex] and [tex]\( 6x \)[/tex], we get:
[tex]\[ f(x) = 3(x^2 + 2x) - 8 \][/tex]

At this point, our function is:
[tex]\[ f(x) = 3(x^2 + 2x) - 8 \][/tex]

This is the first step in the process of transforming the given quadratic function into its vertex form.