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Given that the molar mass of NaCl is [tex]58.44 \, \text{g/mol}[/tex], what is the molarity of a solution that contains 87.75 g of NaCl in [tex]500 \, \text{mL}[/tex] of solution?

Use the formula for molarity: [tex]\text{Molarity} = \frac{\text{moles of solute}}{\text{liters of solution}}[/tex].

A. 0.333 M
B. 0.751 M
C. 1.50 M
D. 3.00 M

Sagot :

GinnyAnsweridn
To determine the molarity of the given NaCl solution, follow these steps:

### Step 1: Identify the Given Data
- Molar mass of NaCl (sodium chloride) = 58.44 g/mol
- Mass of NaCl = 87.75 g
- Volume of the solution = 500 mL

### Step 2: Convert the Volume from mL to Liters
Since 1 L = 1000 mL,
[tex]\[ 500 \, \text{mL} = 0.5 \, \text{L} \][/tex]

### Step 3: Calculate the Number of Moles of NaCl
Using the formula for moles:
[tex]\[ \text{moles of NaCl} = \frac{\text{mass of NaCl}}{\text{molar mass of NaCl}} \][/tex]
[tex]\[ \text{moles of NaCl} = \frac{87.75 \, \text{g}}{58.44 \, \text{g/mol}} \][/tex]
[tex]\[ \text{moles of NaCl} = 1.501540041067762 \, \text{mol} \][/tex]

### Step 4: Calculate the Molarity of the Solution
Molarity is defined as:
[tex]\[ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}} \][/tex]
[tex]\[ \text{Molarity} = \frac{1.501540041067762 \, \text{mol}}{0.5 \, \text{L}} \][/tex]
[tex]\[ \text{Molarity} = 3.003080082135524 \, \text{M} \][/tex]

### Conclusion
The molarity of the solution is approximately 3.00 M.

Thus, the correct answer is:
3.00 M.
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