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Question 13 (Multiple Choice Worth 1 point)

Factor completely [tex]$9x^2 - 25$[/tex].

A. [tex]$(3x + 5)(3x - 5)$[/tex]

B. [tex][tex]$(3x - 5)(3x - 5)$[/tex][/tex]

C. [tex]$(9x + 5)(x - 5)$[/tex]

D. [tex]$(9x - 5)(x + 5)$[/tex]

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Question 14 (Multiple Choice Worth 1 point)

(08.02 MC)


Sagot :

Question 13:
To factor the quadratic expression [tex]\(9x^2 - 25\)[/tex], we recognize that this is a difference of squares. The difference of squares formula is given by [tex]\(a^2 - b^2 = (a - b)(a + b)\)[/tex].

In this case, we can rewrite [tex]\(9x^2\)[/tex] as [tex]\((3x)^2\)[/tex] and [tex]\(25\)[/tex] as [tex]\(5^2\)[/tex]. Therefore, applying the difference of squares formula:

[tex]\[ 9x^2 - 25 = (3x)^2 - 5^2 = (3x - 5)(3x + 5) \][/tex]

So the factored form of the quadratic expression [tex]\(9x^2 - 25\)[/tex] is:
[tex]\[ (3x - 5)(3x + 5) \][/tex]

Thus, the correct answer is:
[tex]\[ (3x + 5)(3x - 5) \][/tex]

Answer: (3x + 5)(3x - 5)

Question 14: [There was no specific question provided for question 14, so I cannot provide a solution.]
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