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Complete the table for the given rule.

Rule: [tex]y = x + 3[/tex]

[tex]\[
\begin{tabular}{cc}
$x$ & $y$ \\
\hline
1 & 4 \\
5 & 8 \\
2 & 5 \\
\end{tabular}
\][/tex]

Sagot :

GinnyAnsweridn
Here's the given rule: [tex]\( y = x + 3 \)[/tex].

We are provided with the rule and need to fill in the missing values in the table based on this rule.

### Step 1: Find [tex]\( y \)[/tex] when [tex]\( x = 4 \)[/tex]

Given [tex]\( x = 4 \)[/tex], we use the rule [tex]\( y = x + 3 \)[/tex]:
[tex]\[ y = 4 + 3 = 7 \][/tex]

So, when [tex]\( x = 4 \)[/tex], [tex]\( y = 7 \)[/tex].

### Step 2: Find [tex]\( x \)[/tex] when [tex]\( y = 8 \)[/tex]

Given [tex]\( y = 8 \)[/tex], we rearrange the rule [tex]\( y = x + 3 \)[/tex] to solve for [tex]\( x \)[/tex]:
[tex]\[ 8 = x + 3 \][/tex]
[tex]\[ x = 8 - 3 = 5 \][/tex]

So, when [tex]\( y = 8 \)[/tex], [tex]\( x = 5 \)[/tex].

### Step 3: Find [tex]\( y \)[/tex] when [tex]\( x = 5 \)[/tex]

Given [tex]\( x = 5 \)[/tex], we use the rule [tex]\( y = x + 3 \)[/tex]:
[tex]\[ y = 5 + 3 = 8 \][/tex]

So, when [tex]\( x = 5 \)[/tex], [tex]\( y = 8 \)[/tex].

### Tabulated Results

Now, we can complete the table and missing values:

[tex]\[ \begin{tabular}{cc} $x$ & $y$ \\ \hline 4 & 7 \\ \square & 8 \\ 5 & \square \\ \end{tabular} \][/tex]

Inserting the calculated values:

[tex]\[ \begin{tabular}{cc} $x$ & $y$ \\ \hline 4 & 7 \\ 5 & 8 \\ 5 & 8 \\ \end{tabular} \][/tex]

Thus, the complete set of pairs is:
[tex]\[ (4, 7), (5, 8), (5, 8) \][/tex]
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