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Multiply.

[tex]\[
\begin{array}{l}
(3r - 1)(4r + 3) \\
(3r - 1)(4r + 3) = \square
\end{array}
\][/tex]

(Simplify your answer.)


Sagot :

To multiply the expressions [tex]\((3r - 1)\)[/tex] and [tex]\((4r + 3)\)[/tex], we can use the distributive property (also known as the FOIL method for binomials). Here’s the step-by-step process:

1. Apply the distributive property for each term in the first binomial to each term in the second binomial (FOIL stands for First, Outer, Inner, Last):

- First: Multiply the first terms in each binomial:
[tex]\[ (3r) \cdot (4r) = 12r^2 \][/tex]

- Outer: Multiply the outer terms in the multiplication:
[tex]\[ (3r) \cdot (3) = 9r \][/tex]

- Inner: Multiply the inner terms:
[tex]\[ (-1) \cdot (4r) = -4r \][/tex]

- Last: Multiply the last terms in each binomial:
[tex]\[ (-1) \cdot (3) = -3 \][/tex]

2. Combine all these results together:
[tex]\[ 12r^2 + 9r - 4r - 3 \][/tex]

3. Simplify by combining like terms (in this case, the [tex]\(r\)[/tex] terms):
[tex]\[ 12r^2 + (9r - 4r) - 3 = 12r^2 + 5r - 3 \][/tex]

Therefore,
[tex]\[ (3r - 1)(4r + 3) = 12r^2 + 5r - 3 \][/tex]

This is the simplified form of the expression.
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