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Select all the equations where [tex]$c=9$[/tex] is a solution.

Choose 2 answers:

A. [tex]4 - c = 5[/tex]
B. [tex]20 = 14 + c[/tex]
C. [tex]15 = c - 6[/tex]
D. [tex]\frac{c}{3} = 3[/tex]
E. [tex]36 = 4c[/tex]


Sagot :

Let's evaluate each equation step by step for [tex]\( c = 9 \)[/tex].

1. For equation A: [tex]\( 4 - c = 5 \)[/tex]
- Substitute [tex]\( c = 9 \)[/tex]:
[tex]\[ 4 - 9 = -5 \neq 5 \][/tex]
- Therefore, [tex]\( c = 9 \)[/tex] is not a solution to this equation.

2. For equation B: [tex]\( 20 = 14 + c \)[/tex]
- Substitute [tex]\( c = 9 \)[/tex]:
[tex]\[ 20 = 14 + 9 = 23 \neq 20 \][/tex]
- Therefore, [tex]\( c = 9 \)[/tex] is not a solution to this equation.

3. For equation (c): [tex]\( 15 = c - 6 \)[/tex]
- Substitute [tex]\( c = 9 \)[/tex]:
[tex]\[ 15 = 9 - 6 = 3 \neq 15 \][/tex]
- Therefore, [tex]\( c = 9 \)[/tex] is not a solution to this equation.

4. For equation D: [tex]\( \frac{c}{3} = 3 \)[/tex]
- Substitute [tex]\( c = 9 \)[/tex]:
[tex]\[ \frac{9}{3} = 3 \][/tex]
- Therefore, [tex]\( c = 9 \)[/tex] is a solution to this equation.

5. For equation E: [tex]\( 36 = 4c \)[/tex]
- Substitute [tex]\( c = 9 \)[/tex]:
[tex]\[ 36 = 4 \times 9 = 36 \][/tex]
- Therefore, [tex]\( c = 9 \)[/tex] is a solution to this equation.

Thus, the solutions are equations D and E.