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Add.
[tex]\[ \frac{5}{x} + \frac{7}{x-4} \][/tex]

[tex]\[ \frac{5}{x} + \frac{7}{x-4} = \ \square \][/tex]

(Simplify your answer.)


Sagot :

To add the fractions [tex]\(\frac{5}{x}\)[/tex] and [tex]\(\frac{7}{x-4}\)[/tex], we need to find a common denominator. The denominators are [tex]\(x\)[/tex] and [tex]\(x-4\)[/tex]. The common denominator will be the product of these two denominators: [tex]\(x \cdot (x - 4) = x(x - 4)\)[/tex].

Next, we express each fraction with this common denominator:

[tex]\[ \frac{5}{x} = \frac{5(x-4)}{x(x-4)} \][/tex]

[tex]\[ \frac{7}{x-4} = \frac{7x}{x(x-4)} \][/tex]

Now add the two fractions:

[tex]\[ \frac{5(x-4)}{x(x-4)} + \frac{7x}{x(x-4)} \][/tex]

Combine the numerators over the common denominator:

[tex]\[ \frac{5(x-4) + 7x}{x(x-4)} \][/tex]

Distribute and simplify the numerator:

[tex]\[ \frac{5x - 20 + 7x}{x(x-4)} = \frac{12x - 20}{x(x-4)} \][/tex]

We can further simplify the numerator by factoring out the common factor of 4:

[tex]\[ \frac{4(3x - 5)}{x(x-4)} \][/tex]

So the simplified form of [tex]\(\frac{5}{x} + \frac{7}{x-4}\)[/tex] is:

[tex]\[ \boxed{\frac{4(3x - 5)}{x(x - 4)}} \][/tex]
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