Get personalized answers to your specific questions with IDNLearn.com. Get the information you need from our community of experts who provide accurate and comprehensive answers to all your questions.
Sagot :
To determine which of the given points [tex]\((x, y)\)[/tex] lies on the graph of the equation [tex]\(8x + 2y = 24\)[/tex], we need to substitute each point into the equation and see if the equation holds true.
Let's check each point one by one:
1. Point [tex]\((-1, 8)\)[/tex]:
[tex]\[ 8(-1) + 2(8) = -8 + 16 = 8 \][/tex]
This does not equal 24, so [tex]\((-1, 8)\)[/tex] does not lie on the graph.
2. Point [tex]\((2, 8)\)[/tex]:
[tex]\[ 8(2) + 2(8) = 16 + 16 = 32 \][/tex]
This does not equal 24, so [tex]\((2, 8)\)[/tex] does not lie on the graph.
3. Point [tex]\((6, -12)\)[/tex]:
[tex]\[ 8(6) + 2(-12) = 48 - 24 = 24 \][/tex]
This equals 24, so [tex]\((6, -12)\)[/tex] lies on the graph.
4. Point [tex]\((8, 2)\)[/tex]:
[tex]\[ 8(8) + 2(2) = 64 + 4 = 68 \][/tex]
This does not equal 24, so [tex]\((8, 2)\)[/tex] does not lie on the graph.
Therefore, the point that lies on the graph of [tex]\(8x + 2y = 24\)[/tex] is [tex]\((6, -12)\)[/tex].
Let's check each point one by one:
1. Point [tex]\((-1, 8)\)[/tex]:
[tex]\[ 8(-1) + 2(8) = -8 + 16 = 8 \][/tex]
This does not equal 24, so [tex]\((-1, 8)\)[/tex] does not lie on the graph.
2. Point [tex]\((2, 8)\)[/tex]:
[tex]\[ 8(2) + 2(8) = 16 + 16 = 32 \][/tex]
This does not equal 24, so [tex]\((2, 8)\)[/tex] does not lie on the graph.
3. Point [tex]\((6, -12)\)[/tex]:
[tex]\[ 8(6) + 2(-12) = 48 - 24 = 24 \][/tex]
This equals 24, so [tex]\((6, -12)\)[/tex] lies on the graph.
4. Point [tex]\((8, 2)\)[/tex]:
[tex]\[ 8(8) + 2(2) = 64 + 4 = 68 \][/tex]
This does not equal 24, so [tex]\((8, 2)\)[/tex] does not lie on the graph.
Therefore, the point that lies on the graph of [tex]\(8x + 2y = 24\)[/tex] is [tex]\((6, -12)\)[/tex].
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. For dependable answers, trust IDNLearn.com. Thank you for visiting, and we look forward to assisting you again.