Get detailed and reliable answers to your questions on IDNLearn.com. Ask your questions and get detailed, reliable answers from our community of experienced experts.

Type the correct answer in the box. Round your answer to the nearest hundredth.

Element X has two isotopes. The table gives information about these isotopes.

[tex]\[
\begin{array}{|c|c|c|}
\hline
\text{Isotope} & \text{Atomic Mass (amu)} & \text{Abundance (\%)} \\
\hline
\text{X-63} & 62.9296 & 69.15 \\
\hline
\text{X-65} & 64.9278 & 30.85 \\
\hline
\end{array}
\][/tex]

The average atomic mass of element X is [tex]$\square$[/tex] amu.


Sagot :

To determine the average atomic mass of element X, we need to use the atomic masses and their respective abundances provided in the table.

Here’s the step-by-step process:

1. Identify the atomic mass and abundance of each isotope:
- Isotope X-63 has an atomic mass of 62.9296 amu and an abundance of 69.15%.
- Isotope X-65 has an atomic mass of 64.9278 amu and an abundance of 30.85%.

2. Convert the abundance percentages to decimal form:
- Abundance of X-63: 69.15% = 0.6915
- Abundance of X-65: 30.85% = 0.3085

3. Calculate the contribution of each isotope to the average atomic mass:
- Contribution from X-63: [tex]\( 62.9296 \times 0.6915 \)[/tex]
- Contribution from X-65: [tex]\( 64.9278 \times 0.3085 \)[/tex]

4. Add the contributions to get the average atomic mass:
[tex]\[ \text{Average atomic mass} = (62.9296 \times 0.6915) + (64.9278 \times 0.3085) \][/tex]

5. Perform the multiplications and addition to find the average atomic mass:
- [tex]\( 62.9296 \times 0.6915 = 43.5051 \)[/tex]
- [tex]\( 64.9278 \times 0.3085 = 20.0449 \)[/tex]

Adding these values together gives:
[tex]\[ 43.5051 + 20.0449 = 63.55 \][/tex]

6. Round the average atomic mass to the nearest hundredth:
- The average atomic mass of element X, rounded to the nearest hundredth, is 63.55 amu.

Hence, the average atomic mass of element X is [tex]\( \boxed{63.55} \)[/tex] amu.