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What is the solution to this equation?

[tex]
\log _7(5 + 11x) = 2
[/tex]

Type the correct answer in the box. Use numerals instead of words.

[tex]
x =
[/tex]


Sagot :

To solve the equation [tex]\(\log_7(5 + 11x) = 2\)[/tex], follow these steps:

1. Rewrite the Logarithmic Equation in Exponential Form:
The equation [tex]\(\log_7(5 + 11x) = 2\)[/tex] implies that [tex]\(7^2 = 5 + 11x\)[/tex].

2. Compute the Exponent:
Calculate [tex]\(7^2\)[/tex]:
[tex]\[ 7^2 = 49 \][/tex]
So, the equation becomes:
[tex]\[ 49 = 5 + 11x \][/tex]

3. Isolate the term containing [tex]\(x\)[/tex]:
Subtract 5 from both sides of the equation to isolate the term with [tex]\(x\)[/tex]:
[tex]\[ 49 - 5 = 11x \][/tex]
Simplify the left-hand side:
[tex]\[ 44 = 11x \][/tex]

4. Solve for [tex]\(x\)[/tex]:
Divide both sides of the equation by 11 to solve for [tex]\(x\)[/tex]:
[tex]\[ x = \frac{44}{11} \][/tex]
Simplify the fraction:
[tex]\[ x = 4 \][/tex]

Therefore, the solution to the equation [tex]\(\log_7(5 + 11x) = 2\)[/tex] is:
[tex]\[ x = 4 \][/tex]

So, the correct answer to the question is:
[tex]\[ \boxed{4} \][/tex]
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