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What is the following product?

[tex]\[
(2 \sqrt{7} + 3 \sqrt{6})(5 \sqrt{2} + 4 \sqrt{3})
\][/tex]

A. [tex]\(6 \sqrt{10} + 16 \sqrt{2} + 42\)[/tex]

B. [tex]\(8 \sqrt{10} + 30 \sqrt{2} + 66\)[/tex]

C. [tex]\(7 \sqrt{14} + 6 \sqrt{21} + 16 \sqrt{3} + 21 \sqrt{2}\)[/tex]

D. [tex]\(10 \sqrt{14} + 8 \sqrt{21} + 30 \sqrt{3} + 36 \sqrt{2}\)[/tex]


Sagot :

To find the product [tex]\((2\sqrt{7} + 3\sqrt{6})(5\sqrt{2} + 4\sqrt{3})\)[/tex], we should use the distributive property of multiplication over addition (also known as the FOIL method in algebra). This gives us:

[tex]\[ (a + b)(c + d) = ac + ad + bc + bd \][/tex]

Let's identify the terms:
- [tex]\(a = 2\sqrt{7}\)[/tex]
- [tex]\(b = 3\sqrt{6}\)[/tex]
- [tex]\(c = 5\sqrt{2}\)[/tex]
- [tex]\(d = 4\sqrt{3}\)[/tex]

Applying the distributive property step-by-step:

1. Calculate [tex]\(ac\)[/tex]:
[tex]\[ 2\sqrt{7} \cdot 5\sqrt{2} = 2 \cdot 5 \cdot \sqrt{7 \cdot 2} = 10 \sqrt{14} \][/tex]

2. Calculate [tex]\(ad\)[/tex]:
[tex]\[ 2\sqrt{7} \cdot 4\sqrt{3} = 2 \cdot 4 \cdot \sqrt{7 \cdot 3} = 8 \sqrt{21} \][/tex]

3. Calculate [tex]\(bc\)[/tex]:
[tex]\[ 3\sqrt{6} \cdot 5\sqrt{2} = 3 \cdot 5 \cdot \sqrt{6 \cdot 2} = 15 \sqrt{12} = 15 \sqrt{4 \cdot 3} = 15 \cdot 2\sqrt{3} = 30 \sqrt{3} \][/tex]

4. Calculate [tex]\(bd\)[/tex]:
[tex]\[ 3\sqrt{6} \cdot 4\sqrt{3} = 3 \cdot 4 \cdot \sqrt{6 \cdot 3} = 12 \sqrt{18} = 12 \sqrt{9 \cdot 2} = 12 \cdot 3\sqrt{2} = 36 \sqrt{2} \][/tex]

Now sum all the terms together:
[tex]\[ 10\sqrt{14} + 8\sqrt{21} + 30\sqrt{3} + 36\sqrt{2} \][/tex]

Thus, the product is:
[tex]\[ 10\sqrt{14} + 8\sqrt{21} + 30\sqrt{3} + 36\sqrt{2} \][/tex]

After evaluating and simplifying each term, we find that our solution matches:

[tex]\[ (10 \sqrt{14}, 8 \sqrt{21}, 30 \sqrt{3}, 36 \sqrt{2}) \][/tex]

Therefore, the correct answer from the given options is:
[tex]\[ 10 \sqrt{14} + 8 \sqrt{21} + 30 \sqrt{3} + 36 \sqrt{2} \][/tex]

So the answer is:
[tex]\[ \boxed{10 \sqrt{14} + 8 \sqrt{21} + 30 \sqrt{3} + 36 \sqrt{2}} \][/tex]