Find answers to your most challenging questions with the help of IDNLearn.com's experts. Our platform provides accurate, detailed responses to help you navigate any topic with ease.
Sagot :
To find [tex]\((f + g)(x)\)[/tex], we need to combine the functions [tex]\(f(x)\)[/tex] and [tex]\(g(x)\)[/tex].
Given:
[tex]\[ f(x) = \frac{x}{2} - 2 \][/tex]
[tex]\[ g(x) = 2x^2 + x - 3 \][/tex]
Our goal is to add these two expressions together, that is,
[tex]\[ (f + g)(x) = f(x) + g(x) \][/tex]
Let's write out the functions with the same variable [tex]\(x\)[/tex]:
[tex]\[ (f + g)(x) = \left( \frac{x}{2} - 2 \right) + \left( 2x^2 + x - 3 \right) \][/tex]
To add these expressions, we combine like terms:
1. Combine the [tex]\(x^2\)[/tex] terms:
[tex]\[ 2x^2 \][/tex]
2. Combine the [tex]\(x\)[/tex] terms:
[tex]\[ \frac{x}{2} + x = \frac{x}{2} + \frac{2x}{2} = \frac{3x}{2} \][/tex]
3. Combine the constant terms:
[tex]\[ -2 - 3 = -5 \][/tex]
Putting these together, we get:
[tex]\[ 2x^2 + \frac{3x}{2} - 5 \][/tex]
So, the resulting function [tex]\((f + g)(x)\)[/tex] is:
[tex]\[ (f + g)(x) = 2x^2 + \frac{3x}{2} - 5 \][/tex]
This is our final expression.
Given:
[tex]\[ f(x) = \frac{x}{2} - 2 \][/tex]
[tex]\[ g(x) = 2x^2 + x - 3 \][/tex]
Our goal is to add these two expressions together, that is,
[tex]\[ (f + g)(x) = f(x) + g(x) \][/tex]
Let's write out the functions with the same variable [tex]\(x\)[/tex]:
[tex]\[ (f + g)(x) = \left( \frac{x}{2} - 2 \right) + \left( 2x^2 + x - 3 \right) \][/tex]
To add these expressions, we combine like terms:
1. Combine the [tex]\(x^2\)[/tex] terms:
[tex]\[ 2x^2 \][/tex]
2. Combine the [tex]\(x\)[/tex] terms:
[tex]\[ \frac{x}{2} + x = \frac{x}{2} + \frac{2x}{2} = \frac{3x}{2} \][/tex]
3. Combine the constant terms:
[tex]\[ -2 - 3 = -5 \][/tex]
Putting these together, we get:
[tex]\[ 2x^2 + \frac{3x}{2} - 5 \][/tex]
So, the resulting function [tex]\((f + g)(x)\)[/tex] is:
[tex]\[ (f + g)(x) = 2x^2 + \frac{3x}{2} - 5 \][/tex]
This is our final expression.
Thank you for using this platform to share and learn. Keep asking and answering. We appreciate every contribution you make. Thank you for choosing IDNLearn.com. We’re committed to providing accurate answers, so visit us again soon.