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What is the molarity of a solution that contains 192.3 g NaCl (molar mass = 58.44 g/mol) in 0.6 L solution?

Sagot :

BrotherGokuidn

Answer:

5.484mol (5mol)

Explanation:

The molarity is the number of moles of a substance over a given volume in litres. Since we are given the volume, what we need is the numebr of moles of NaCl.

Given the mass of NaCl and knowing the relation M = m/n, where M is the molar mass, m is the mass and n is the number of moles, swap the units of n and M, for which you get n = m/M.

Now that we have the mass and the molar mass, we can find the number of moles by doing 192.3/58.44 = 3.2906 mols of NaCl.

Now all there is left is to divide the number of mols found by the volume.

3.2906/0.6 = 5.484 mol/L (1 s.f. from 0.6L so 5 mol/l)

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