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What is the radius of a circle whose equation is [tex]$x^2 + y^2 = 64$[/tex]?

A. 32
B. 16
C. 8
D. 64


Sagot :

To determine the radius of the circle given the equation [tex]\(x^2 + y^2 = 64\)[/tex], we will compare it with the standard form of a circle's equation.

1. Understand the Standard Form: The standard form of the equation for a circle centered at the origin ([tex]\(0, 0\)[/tex]) is [tex]\(x^2 + y^2 = r^2\)[/tex], where [tex]\(r\)[/tex] is the radius of the circle.

2. Identify [tex]\(r^2\)[/tex]: From the given equation [tex]\(x^2 + y^2 = 64\)[/tex], we see that [tex]\(r^2 = 64\)[/tex].

3. Solve for [tex]\(r\)[/tex]: To find the radius ([tex]\(r\)[/tex]):
[tex]\[ r = \sqrt{64} \][/tex]

4. Calculate the Numerical Value:
[tex]\[ \sqrt{64} = 8 \][/tex]

Therefore, the radius of the circle is [tex]\(8\)[/tex].

The correct answer is:
C. 8