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How many bricks of size 22 cm x 10 cm x 7 cm are required to construct a wall that is 33 m long, 3.5 m high, and 40 cm thick, if cement and sand used in the construction occupy [tex]\(\frac{1}{10}\)[/tex] part of the wall?

(a) 27,000
(b) 30,000
(c) 21,000
(d) 50,000


Sagot :

To determine the number of bricks needed to construct the wall, we need to carry out the following steps:

1. Convert the dimensions of the wall to consistent units (centimeters):

- Wall length: 33 meters = 33 100 cm = 3300 cm
- Wall height: 3.5 meters = 3.5
100 cm = 350 cm
- Wall thickness: 40 cm (already in centimeters)

2. Calculate the volume of the wall (in cubic centimeters):

The volume [tex]\( V \)[/tex] of a rectangular solid (wall) is given by:

[tex]\[ V_{\text{wall}} = \text{length} \times \text{height} \times \text{thickness} \][/tex]

Substituting the values:

[tex]\[ V_{\text{wall}} = 3300 \, \text{cm} \times 350 \, \text{cm} \times 40 \, \text{cm} = 46200000 \, \text{cm}^3 \][/tex]

3. Calculate the volume of one brick (in cubic centimeters):

The volume [tex]\( V \)[/tex] of a brick is given by:

[tex]\[ V_{\text{brick}} = \text{length} \times \text{width} \times \text{height} \][/tex]

Given the dimensions of the brick:

[tex]\[ V_{\text{brick}} = 22 \, \text{cm} \times 10 \, \text{cm} \times 7 \, \text{cm} = 1540 \, \text{cm}^3 \][/tex]

4. Determine the usable volume of the wall for bricks (considering 1/10 part occupied by cement and sand):

Only 9/10 of the wall's volume will be occupied by bricks:

[tex]\[ V_{\text{usable wall}} = V_{\text{wall}} \times \frac{9}{10} \][/tex]

Substituting the volume of the wall:

[tex]\[ V_{\text{usable wall}} = 46200000 \, \text{cm}^3 \times \frac{9}{10} = 41580000 \, \text{cm}^3 \][/tex]

5. Calculate the number of bricks needed:

The number of bricks can be determined by dividing the usable volume of the wall by the volume of one brick:

[tex]\[ \text{Number of bricks} = \frac{V_{\text{usable wall}}}{V_{\text{brick}}} \][/tex]

Substituting the values:

[tex]\[ \text{Number of bricks} = \frac{41580000 \, \text{cm}^3}{1540 \, \text{cm}^3} = 27000 \, \text{bricks} \][/tex]

Therefore, the number of bricks required to construct the wall is [tex]\(\boxed{27000}\)[/tex].

So, the correct option is:
(a) 27000