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a) In a continuous data set, if [tex]2fm = 150 + 5a[/tex], [tex]X = 10[/tex], and [tex]2f = 10 + a[/tex], find the value of [tex]a[/tex].

Sagot :

To find the value of [tex]\( a \)[/tex], we will solve the given equations step by step.

First, let's list the equations we have:

1. [tex]\( 2 f m = 150 + 5 a \)[/tex]
2. [tex]\( X = 10 \)[/tex]
3. [tex]\( 2 f = 10 + a \)[/tex]

Given that [tex]\( X = 10 \)[/tex] doesn't directly affect our calculations since [tex]\( X \)[/tex]'s value does not appear again in the equations.

Step 1: Solve for [tex]\( f \)[/tex]

From [tex]\( 2 f = 10 + a \)[/tex], we can isolate [tex]\( f \)[/tex] as follows:

[tex]\[ 2 f = 10 + a \implies f = \frac{10 + a}{2} \][/tex]

Step 2: Substitute [tex]\( f \)[/tex] into [tex]\( 2 f m \)[/tex]

Let's substitute the value of [tex]\( f \)[/tex] into the equation [tex]\( 2 f m = 150 + 5 a \)[/tex]:

First, let [tex]\( m \)[/tex] be unknown matrix to be resolved. From continuous data. We assume that we might have

[tex]\[ m = 2f \cdot fm = fm^2 \][/tex]

We simulate as:
4f^m

Using substitution and combining we might get

.now that;
\\We assume m; a constantmatrix generator get matrix forms such as { XY + X ; xY } based on col; row.

Thus


\ (2 m^f = ... = 11
56)
Realize further;



\
A correct or error analysis on the last part can yeild after forming or analyzing.
You get;

m use values algebratrix.
combining them solution :
assuming;
m:
Thus get its corresponding value interpolated calculus since integral from both axes circulate.