Connect with a community of experts and enthusiasts on IDNLearn.com. Discover comprehensive answers to your questions from our community of knowledgeable experts.

If triangle [tex]$XYZ$[/tex] is translated using the rule [tex]$(x, y) \rightarrow (x+5, y-3)$[/tex] and then rotated [tex][tex]$90^{\circ}$[/tex][/tex] clockwise to create triangle [tex]$X'Y'Z'$[/tex], what is the location of [tex]$X'$[/tex]?

A. [tex]$(-3, 10)$[/tex]
B. [tex][tex]$(-2, -15)$[/tex][/tex]
C. [tex]$(-2, -7)$[/tex]
D. [tex]$(3, -10)$[/tex]


Sagot :

Let's analyze the given transformations step-by-step for the point [tex]\(X\)[/tex] with coordinates [tex]\((-3, 10)\)[/tex].

### Step 1: Translation
The translation rule given is [tex]\((x, y) \rightarrow (x+5, y-3)\)[/tex].

Applying the translation to [tex]\(X\)[/tex]:
[tex]\[ x' = -3 + 5 = 2 \][/tex]
[tex]\[ y' = 10 - 3 = 7 \][/tex]

So, after the translation, the coordinates of [tex]\(X\)[/tex] are [tex]\((2, 7)\)[/tex].

### Step 2: Rotation
The rotation rule for a [tex]\(90^\circ\)[/tex] clockwise rotation is [tex]\((x, y) \rightarrow (y, -x)\)[/tex].

Applying the rotation to the translated coordinates [tex]\((2, 7)\)[/tex]:
[tex]\[ x'' = y' = 7 \][/tex]
[tex]\[ y'' = -x' = -2 \][/tex]

So, after the rotation, the coordinates of [tex]\(X\)[/tex] are [tex]\((7, -2)\)[/tex].

### Conclusion
The location of [tex]\(X'\)[/tex] after translating the point [tex]\((-3, 10)\)[/tex] using the rule [tex]\((x, y) \rightarrow (x+5, y-3)\)[/tex] and then rotating the point [tex]\(90^\circ\)[/tex] clockwise is [tex]\((7, -2)\)[/tex].

Thus, the correct answer is not listed among the provided options exactly, but analyzing the given details, the closest matching step appears to be:
[tex]\[ (7, -2) \][/tex]
Which is not in the provided options—seems like there is a discrepancy or error in problem statement options.

Therefore, please reach out for further clarification or correction in the options provided.
We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Thank you for trusting IDNLearn.com with your questions. Visit us again for clear, concise, and accurate answers.