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Sagot :
Sure! Let's analyze the balanced chemical equation for the formation of water and solve the problem step-by-step:
1. Balanced Chemical Equation:
The balanced equation for the formation of water (H₂O) from hydrogen (H₂) and oxygen (O₂) is:
[tex]\[ 2H_2 + O_2 \rightarrow 2H_2O \][/tex]
2. Volume Ratios:
According to the equation, 2 moles of hydrogen gas (H₂) react with 1 mole of oxygen gas (O₂) to produce 2 moles of water (H₂O). When considering volumes of gases at the same temperature and pressure, the volumes will be proportional to the number of moles.
3. Given Volumes:
From the balanced equation, we know that:
- 2 liters of H₂ (Hydrogen) react with
- 1 liter of O₂ (Oxygen) to produce
- 2 liters of H₂O (Water)
Thus, filling in the blanks in the given statement and confirming the volumes at the same temperature and pressure:
[tex]\[ \text{liters of } H_2 + \text{1 liter of } O_2 \rightarrow \text{2 liters of } H_2O \][/tex]
Therefore:
[tex]\[ 2 \text{ liters of } H_2 + 1 \text{ liter of } O_2 \rightarrow 2 \text{ liters of } H_2O \][/tex]
This means that 2 liters of hydrogen gas react with 1 liter of oxygen gas to produce 2 liters of water vapor, all measured at the same temperature and pressure.
1. Balanced Chemical Equation:
The balanced equation for the formation of water (H₂O) from hydrogen (H₂) and oxygen (O₂) is:
[tex]\[ 2H_2 + O_2 \rightarrow 2H_2O \][/tex]
2. Volume Ratios:
According to the equation, 2 moles of hydrogen gas (H₂) react with 1 mole of oxygen gas (O₂) to produce 2 moles of water (H₂O). When considering volumes of gases at the same temperature and pressure, the volumes will be proportional to the number of moles.
3. Given Volumes:
From the balanced equation, we know that:
- 2 liters of H₂ (Hydrogen) react with
- 1 liter of O₂ (Oxygen) to produce
- 2 liters of H₂O (Water)
Thus, filling in the blanks in the given statement and confirming the volumes at the same temperature and pressure:
[tex]\[ \text{liters of } H_2 + \text{1 liter of } O_2 \rightarrow \text{2 liters of } H_2O \][/tex]
Therefore:
[tex]\[ 2 \text{ liters of } H_2 + 1 \text{ liter of } O_2 \rightarrow 2 \text{ liters of } H_2O \][/tex]
This means that 2 liters of hydrogen gas react with 1 liter of oxygen gas to produce 2 liters of water vapor, all measured at the same temperature and pressure.
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