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Solve for [tex]$y$[/tex].
Assume the equation has a solution for [tex]$y$[/tex].

[tex]\[ a \cdot (n + y) = 10y + 32 \][/tex]

[tex]\[ y = \square \][/tex]

Sagot :

GinnyAnsweridn
To solve for [tex]\( y \)[/tex] in the equation

[tex]\[ a \cdot (n + y) = 10y + 32, \][/tex]

we need to isolate [tex]\( y \)[/tex]. Follow these steps:

1. Distribute [tex]\( a \)[/tex] on the left-hand side of the equation:

[tex]\[ a \cdot n + a \cdot y = 10y + 32. \][/tex]

2. Move all the terms involving [tex]\( y \)[/tex] to one side of the equation:

[tex]\[ a \cdot n + a \cdot y - 10y = 32. \][/tex]

This can be simplified to:

[tex]\[ a \cdot y - 10y = 32 - a \cdot n. \][/tex]

3. Factor out [tex]\( y \)[/tex] from the left-hand side:

[tex]\[ y(a - 10) = 32 - a \cdot n. \][/tex]

4. Solve for [tex]\( y \)[/tex] by dividing both sides by [tex]\( a - 10 \)[/tex]:

[tex]\[ y = \frac{32 - a \cdot n}{a - 10}. \][/tex]

Thus, the solution for [tex]\( y \)[/tex] is:

[tex]\[ y = \frac{32 - a \cdot n}{a - 10}. \][/tex]
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