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The two-way table shows the number of sport utility vehicles with certain features for sale at the car lot.

\begin{tabular}{|c|c|c|c|}
\hline & \begin{tabular}{c}
4-Wheel \\
Drive
\end{tabular} & \begin{tabular}{c}
No 4-Wheel \\
Drive
\end{tabular} & Total \\
\hline Third-Row Seats & 18 & 12 & 30 \\
\hline No Third-Row Seats & 7 & 28 & 35 \\
\hline Total & 25 & 40 & 65 \\
\hline
\end{tabular}

What is the probability that a randomly selected car with no 4-wheel drive has third-row seats?

A. 0.3
B. 0.4
C. 0.7
D. 0.8

Sagot :

GinnyAnsweridn
To find the probability that a randomly selected car with no 4-wheel drive has third-row seats, we need to analyze the given two-way table.

The table provides the following information:
- The total number of cars that have no 4-wheel drive.
- The number of cars that have no 4-wheel drive and have third-row seats.

From the table:
- The total number of cars that have no 4-wheel drive is 40.
- The number of cars that have no 4-wheel drive and have third-row seats is 12.

The probability can be found using the formula for probability:
[tex]\[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \][/tex]

Here, the number of favorable outcomes is the number of cars with no 4-wheel drive that have third-row seats, which is 12. The total number of outcomes is the total number of cars with no 4-wheel drive, which is 40.

So, the probability is:
[tex]\[ \text{Probability} = \frac{12}{40} = 0.3 \][/tex]

Thus, the probability that a randomly selected car with no 4-wheel drive has third-row seats is [tex]\(0.3\)[/tex].

The correct answer is [tex]\(0.3\)[/tex].
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