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can anyone help me?

(about angle and tangent)​


Can Anyone Help Meabout Angle And Tangent class=

Sagot :

Answer:

x = 18⁰

Step-by-step explanation:

Angle AOB = 90⁰ ( angle in a semi-circle)

Angle BQP = 2x ( angle in the alternate segment i.e angle between a chord and a tangent is equal to the angle the chord subtends in the alternate segment)

Considering the triangle AQP,

2x + (90⁰ + 2x) + x = 180⁰ (sum of angles in a triangle)

5x + 90⁰ = 180⁰

5x = 180⁰ - 90⁰

5x = 90⁰ Divide both sides by 5

x = 18⁰

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