Discover new perspectives and gain insights with IDNLearn.com's diverse answers. Join our community to receive prompt and reliable responses to your questions from knowledgeable professionals.
Sagot :
Sure, let's find [tex]\( f(c) \)[/tex] using synthetic substitution for the given polynomial [tex]\( f(x) = -x^7 + 4x^6 - 4x^5 - 6x^4 - 3x^3 - 6x^2 - x - 2 \)[/tex] at [tex]\( c = -5 \)[/tex].
Here's a step-by-step method to carry out the synthetic substitution:
1. Set Up the Coefficients:
[tex]\[ \text{Coefficients of } f(x): -1, 4, -4, -6, -3, -6, -1, -2 \][/tex]
2. Write Down the Value of [tex]\( c \)[/tex]:
[tex]\[ c = -5 \][/tex]
3. Perform the Synthetic Substitution Process:
- Write down the coefficient sequence.
- Draw a horizontal line below it.
- Write [tex]\( c \)[/tex] to the left outside the grid.
[tex]\[ \begin{array}{r|rrrrrrrr} -5 & -1 & 4 & -4 & -6 & -3 & -6 & -1 & -2 \\ \hline & & & & & & & & \\ & -1 & & & & & & & \\ \end{array} \][/tex]
4. Carry Down the Leading Coefficient: First step is to carry down the leading coefficient (-1):
[tex]\[ \begin{array}{r|rrrrrrrr} -5 & -1 & 4 & -4 & -6 & -3 & -6 & -1 & -2 \\ \hline & & & & & & & & \\ & -1 & & & & & & & \\ \end{array} \][/tex]
5. Multiply and Add:
- Multiply the carried-down number by [tex]\( c = -5 \)[/tex] and write the result under the next coefficient.
- Add the numbers in the second row and write the result in the third row.
[tex]\[ \begin{array}{r|rrrrrrrr} -5 & -1 & 4 & -4 & -6 & -3 & -6 & -1 & -2 \\ \hline & & & & & & & & \\ & -1 & 5 & & & & & & \\ \end{array} \][/tex]
Now:
[tex]\[ 4 + 5 = 9 \][/tex]
Continue this process:
[tex]\[ \begin{array}{r|rrrrrrrr} -5 & -1 & 4 & -4 & -6 & -3 & -6 & -1 & -2 \\ \hline & & & & & & & & \\ & -1 & 5 & 9 & -49 & 239 & -1188 & 5934 & -29671 \\ \end{array} \][/tex]
Check this calculation continuing step-by-step:
[tex]\[ \begin{array}{r|rrrrrrrr} -5 & -1 & 4 & -4 & -6 & -3 & -6 & -1 & -2 \\ \hline & & & & & & & & \\ & -1 & 5 & -21 & -94 & 464 & -2312 & 11559 & -57807 \\ -1 & 5 & -21 & 94 & -437 & 2301 & -11695 & 57975 & -288797 \end{array} \][/tex]
Thus, following all the steps of our synthetic substitution:
[tex]\[ f(-5) = 149,603 \][/tex]
This yields the desired output.
Here's a step-by-step method to carry out the synthetic substitution:
1. Set Up the Coefficients:
[tex]\[ \text{Coefficients of } f(x): -1, 4, -4, -6, -3, -6, -1, -2 \][/tex]
2. Write Down the Value of [tex]\( c \)[/tex]:
[tex]\[ c = -5 \][/tex]
3. Perform the Synthetic Substitution Process:
- Write down the coefficient sequence.
- Draw a horizontal line below it.
- Write [tex]\( c \)[/tex] to the left outside the grid.
[tex]\[ \begin{array}{r|rrrrrrrr} -5 & -1 & 4 & -4 & -6 & -3 & -6 & -1 & -2 \\ \hline & & & & & & & & \\ & -1 & & & & & & & \\ \end{array} \][/tex]
4. Carry Down the Leading Coefficient: First step is to carry down the leading coefficient (-1):
[tex]\[ \begin{array}{r|rrrrrrrr} -5 & -1 & 4 & -4 & -6 & -3 & -6 & -1 & -2 \\ \hline & & & & & & & & \\ & -1 & & & & & & & \\ \end{array} \][/tex]
5. Multiply and Add:
- Multiply the carried-down number by [tex]\( c = -5 \)[/tex] and write the result under the next coefficient.
- Add the numbers in the second row and write the result in the third row.
[tex]\[ \begin{array}{r|rrrrrrrr} -5 & -1 & 4 & -4 & -6 & -3 & -6 & -1 & -2 \\ \hline & & & & & & & & \\ & -1 & 5 & & & & & & \\ \end{array} \][/tex]
Now:
[tex]\[ 4 + 5 = 9 \][/tex]
Continue this process:
[tex]\[ \begin{array}{r|rrrrrrrr} -5 & -1 & 4 & -4 & -6 & -3 & -6 & -1 & -2 \\ \hline & & & & & & & & \\ & -1 & 5 & 9 & -49 & 239 & -1188 & 5934 & -29671 \\ \end{array} \][/tex]
Check this calculation continuing step-by-step:
[tex]\[ \begin{array}{r|rrrrrrrr} -5 & -1 & 4 & -4 & -6 & -3 & -6 & -1 & -2 \\ \hline & & & & & & & & \\ & -1 & 5 & -21 & -94 & 464 & -2312 & 11559 & -57807 \\ -1 & 5 & -21 & 94 & -437 & 2301 & -11695 & 57975 & -288797 \end{array} \][/tex]
Thus, following all the steps of our synthetic substitution:
[tex]\[ f(-5) = 149,603 \][/tex]
This yields the desired output.
Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. IDNLearn.com provides the answers you need. Thank you for visiting, and see you next time for more valuable insights.