IDNLearn.com: Where questions are met with accurate and insightful answers. Get timely and accurate answers to your questions from our dedicated community of experts who are here to help you.
Sagot :
Answer:
Acceleration of the center of the disc:
a = (T - Mg + N) / M
Angular acceleration of the disc:
α = 2 × T / (M × r)
Since N = Mg (equilibrium) and g = 9.8 m/s^2 (standard gravity), we can simplify the expressions:
a = (T - Mg + Mg) / M = T / M
α = 2 × T / (M × r)
So, the answers are:
a = T / M
α = 2 × T / (M × r)
Please note that these are general expressions, and you'll need to plug in specific values for T, M, and r to get numerical answers.
Explanation:
classic problem in mechanics!
Let's break it down step by step:
1. ** Forces acting on the disc **:
- Force of gravity (Mg) acting downwards
- Normal force (N) acting upwards from the rough surface
- Force of tension (T) in the thread, acting tangentially
- Friction force (f) acting opposite to the motion
2. ** Motion of the disc **:
- The disc rolls without slipping, so the point of contact with the surface is at rest.
- The center of the disc moves with acceleration (a)
- The disc rotates with angular acceleration (α)
3. ** Equations of motion **:
- For linear motion: Mg - N + T = Ma (since f = 0, no slipping)
For rotational motion: T × r = I × α (where I is the moment of inertia of the disc)
4. ** Moment of inertia **:
- For a uniform disc: I = (1/2) × M × r^2
5. ** Solving for a and α **:
- From the linear motion equation: a = (T - Mg + N) / M
- From the rotational motion equation: α = T × r / I = T × r / (0.5 × M × r^2) = 2 × T / (M × r)
So, the acceleration of the center of the disc is:
a = (T - Mg + N) / M
And the angular acceleration of the disc is:
α = 2 × T / (M × r)
Note that N = Mg if the disc is in equilibrium, and f = 0 since it rolls without slipping. You can plug in the values of T, M, r, and g to find the numerical values of a and α.
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Discover the answers you need at IDNLearn.com. Thank you for visiting, and we hope to see you again for more solutions.