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Learning Goal:
To use partial pressures in gas law calculations.

In a mixture of gases, the total pressure of the gas mixture is equal to the sum of the partial pressures of the individual gases. For example, if you have a mixture of helium at 2 atm and argon at 4 atm, then the total pressure of the gas inside the cylinder is 6 atm.

Part A:

A mixture of He, Ar, and Xe has a total pressure of 2.10 atm. The partial pressure of He is 0.300 atm, and the partial pressure of Ar is 0.450 atm. What is the partial pressure of Xe?

Express your answer to three significant figures and include the appropriate units.

[tex]\[ P_{\text{Xe}} = \ \boxed{} \ \text{Value} \ \text{Units} \][/tex]


Sagot :

To determine the partial pressure of xenon (Xe) in the gas mixture, you should follow these steps:

1. Understand the Relationship Between Total and Partial Pressures:
The total pressure of a gas mixture is the sum of the partial pressures of the individual gases in the mixture. This can be expressed as:
[tex]\[ P_{\text{total}} = P_{\text{He}} + P_{\text{Ar}} + P_{\text{Xe}} \][/tex]

2. Identify the Given Values:
- Total pressure ([tex]\(P_{\text{total}}\)[/tex]): 2.10 atm
- Partial pressure of helium ([tex]\(P_{\text{He}}\)[/tex]): 0.300 atm
- Partial pressure of argon ([tex]\(P_{\text{Ar}}\)[/tex]): 0.450 atm

3. Set Up the Equation:
Using the given values, substitute them into the equation:
[tex]\[ 2.10 \, \text{atm} = 0.300 \, \text{atm} + 0.450 \, \text{atm} + P_{\text{Xe}} \][/tex]

4. Solve for the Partial Pressure of Xenon ([tex]\(P_{\text{Xe}}\)[/tex]):
Rearrange the equation to isolate [tex]\(P_{\text{Xe}}\)[/tex]:
[tex]\[ P_{\text{Xe}} = 2.10 \, \text{atm} - (0.300 \, \text{atm} + 0.450 \, \text{atm}) \][/tex]
[tex]\[ P_{\text{Xe}} = 2.10 \, \text{atm} - 0.750 \, \text{atm} \][/tex]
[tex]\[ P_{\text{Xe}} = 1.35 \, \text{atm} \][/tex]

Thus, the partial pressure of Xe in the mixture is [tex]\(1.35\)[/tex] atm.