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What is the [tex]$y$[/tex]-intercept of the function [tex]$f(x)=\frac{2}{9} x+\frac{1}{3}$[/tex]?

A. [tex]$-\frac{2}{9}$[/tex]
B. [tex]$-\frac{1}{3}$[/tex]
C. [tex]$\frac{1}{3}$[/tex]
D. [tex]$\frac{7}{9}$[/tex]


Sagot :

To find the [tex]\( y \)[/tex]-intercept of the linear function [tex]\( f(x) = \frac{2}{9} x + \frac{1}{3} \)[/tex], we need to focus on the constant term in the equation. This constant term is what [tex]\( f(x) \)[/tex] equals when [tex]\( x = 0 \)[/tex].

Here’s the step-by-step process:

1. Understand the structure of a linear equation: A linear function is generally written in the form [tex]\( y = mx + b \)[/tex], where [tex]\( m \)[/tex] is the slope and [tex]\( b \)[/tex] is the [tex]\( y \)[/tex]-intercept.

2. Identify the [tex]\( y \)[/tex]-intercept: In the equation [tex]\( f(x) = \frac{2}{9} x + \frac{1}{3} \)[/tex], you need to identify the constant term, which represents the [tex]\( y \)[/tex]-intercept. This constant term is the value of the function when [tex]\( x = 0 \)[/tex].

3. Set [tex]\( x \)[/tex] to 0:
[tex]\[ f(0) = \frac{2}{9} (0) + \frac{1}{3} \][/tex]

4. Calculate the value:
[tex]\[ f(0) = 0 + \frac{1}{3} \][/tex]
[tex]\[ f(0) = \frac{1}{3} \][/tex]

The [tex]\( y \)[/tex]-intercept is therefore [tex]\( \frac{1}{3} \)[/tex].

Given the options:
- [tex]\(-\frac{2}{9}\)[/tex]
- [tex]\(-\frac{1}{3}\)[/tex]
- [tex]\(\frac{1}{3}\)[/tex]
- [tex]\(\frac{7}{9}\)[/tex]

The correct answer is [tex]\( \frac{1}{3} \)[/tex].
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