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For the reaction [tex]$CH _3 COOH \rightarrow CH _3 COO ^{-}+ H ^{+}$[/tex], which statement is true?

A. [tex]CH _3 COOH[/tex] is a Brønsted-Lowry base.
B. [tex]CH _3 COOH[/tex] is a Brønsted-Lowry acid.
C. [tex]CH _3 COO ^{-}[/tex] is an Arrhenius base.
D. [tex]CH _3 COO ^{-}[/tex] is a Lewis base.

Sagot :

GinnyAnsweridn
To determine the validity of each statement regarding the reaction:

[tex]\[ CH_3COOH \rightarrow CH_3COO^{-} + H^{+} \][/tex]

we need to analyze the roles of [tex]\(CH_3COOH\)[/tex] and [tex]\(CH_3COO^{-}\)[/tex] based on different definitions of acids and bases.

1. Statement: [tex]\(CH_3COOH\)[/tex] is a Brønsted-Lowry base.

The Brønsted-Lowry theory defines an acid as a proton (H[tex]\(^+\)[/tex]) donor and a base as a proton acceptor. In the reaction

[tex]\[ CH_3COOH \rightarrow CH_3COO^{-} + H^{+}, \][/tex]

[tex]\(CH_3COOH\)[/tex] is donating a proton (H[tex]\(^+\)[/tex]), hence it acts as a Brønsted-Lowry acid, not a base. Therefore, this statement is False.

2. Statement: [tex]\(CH_3COOH\)[/tex] is a Brønsted-Lowry acid.

As mentioned above, since [tex]\(CH_3COOH\)[/tex] donates a proton (H[tex]\(^+\)[/tex]), it is a Brønsted-Lowry acid. Thus, this statement is True.

3. Statement: [tex]\(CH_3COO^{-}\)[/tex] is an Arrhenius base.

The Arrhenius definition states that an Arrhenius base is a substance that increases the concentration of OH[tex]\(^-\)[/tex] ions in aqueous solution. In this reaction, [tex]\(CH_3COO^{-}\)[/tex] does not directly release OH[tex]\(^-\)[/tex] ions. Thus, this statement is False.

4. Statement: [tex]\(CH_3COO^{-}\)[/tex] is a Lewis base.

According to the Lewis definition, a base is a substance that donates an electron pair. The acetate ion ([tex]\(CH_3COO^{-}\)[/tex]) has lone pairs of electrons that it can donate, qualifying it as a Lewis base. Hence, this statement is True.

So, summarizing the evaluation of the statements:

1. False - [tex]\(CH_3COOH\)[/tex] is not a Brønsted-Lowry base.
2. True - [tex]\(CH_3COOH\)[/tex] is a Brønsted-Lowry acid.
3. False - [tex]\(CH_3COO^{-}\)[/tex] is not an Arrhenius base.
4. True - [tex]\(CH_3COO^{-}\)[/tex] is a Lewis base.

Therefore, the correct answer is:

[tex]\[ (False, True, False, True) \][/tex]
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