To find the electric potential [tex]\( V \)[/tex] at a point due to a charge, we can use the relationship between electric potential energy and electric potential. The formula we will use is:
[tex]\[ V = \frac{U}{q} \][/tex]
where:
- [tex]\( V \)[/tex] is the electric potential,
- [tex]\( U \)[/tex] is the electric potential energy,
- [tex]\( q \)[/tex] is the charge.
Let's identify the given values:
- The charge [tex]\( q \)[/tex] is [tex]\( 7.2 \times 10^{-5} \)[/tex] Coulombs.
- The electric potential energy [tex]\( U \)[/tex] is [tex]\( 1.08 \times 10^{-2} \)[/tex] Joules.
Now, substituting the given values into the formula:
[tex]\[ V = \frac{1.08 \times 10^{-2}}{7.2 \times 10^{-5}} \][/tex]
Dividing these values:
[tex]\[ V = \frac{1.08 \times 10^{-2}}{7.2 \times 10^{-5}} = 150.0 \][/tex]
So, the electric potential [tex]\( V \)[/tex] is 150.0 volts.
To find the electric potential to the nearest whole number, we round 150.0 to the nearest integer.
Thus, the electric potential to the nearest whole number is:
[tex]\[ V \approx 150 \text{ V} \][/tex]
Therefore, the electric potential is [tex]\( \boxed{150} \)[/tex] volts.
