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Example:

[tex]\[
\begin{array}{c}
(10 + 3) - 8 = 2 + 3 \\
13 - 8 = 5 \\
(10 - 3) - 8 = 2 - 3 \\
7 - 8 = -1
\end{array}
\][/tex]

Sagot :

GinnyAnsweridn
Sure, let's solve each of the given equations step-by-step.

### Equation 1: (10 + 3) - 8 = 2 + 3
1. Compute the left-hand side:
- First, inside the parentheses: [tex]\(10 + 3 = 13\)[/tex].
- Then, subtract 8 from 13: [tex]\(13 - 8 = 5\)[/tex].
2. Compute the right-hand side:
- Add 2 and 3 directly: [tex]\(2 + 3 = 5\)[/tex].
3. Compare the results from both sides:
- Left-hand side: 5
- Right-hand side: 5

Since both sides are equal, the equation holds true.

### Equation 2: 13 - 8 = 5
1. Compute the left-hand side directly:
- Subtract 8 from 13: [tex]\(13 - 8 = 5\)[/tex].
2. The right-hand side is given directly as 5.

Compare the results from both sides:
- Left-hand side: 5
- Right-hand side: 5

Since both sides are equal, the equation holds true.

### Equation 3: (10 - 3) - 8 = 2 - 3
1. Compute the left-hand side:
- First, inside the parentheses: [tex]\(10 - 3 = 7\)[/tex].
- Then, subtract 8 from 7: [tex]\(7 - 8 = -1\)[/tex].
2. Compute the right-hand side:
- Subtract 3 from 2: [tex]\(2 - 3 = -1\)[/tex].
3. Compare the results from both sides:
- Left-hand side: -1
- Right-hand side: -1

Since both sides are equal, the equation holds true.

### Equation 4: 7 - 8 = -1
1. Compute the left-hand side directly:
- Subtract 8 from 7: [tex]\(7 - 8 = -1\)[/tex].
2. The right-hand side is given directly as -1.

Compare the results from both sides:
- Left-hand side: -1
- Right-hand side: -1

Since both sides are equal, the equation holds true.

Therefore, all provided comparisons are correct, and each of the equations holds true.
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