Get expert insights and community-driven knowledge on IDNLearn.com. Find the information you need quickly and easily with our comprehensive and accurate Q&A platform.
Sagot :
Sure! Let's go through the solution step by step.
### Part 1: General Indefinite Integral
We need to find the general indefinite integral of the function [tex]\( 8t^3 - 6t^{-2} \)[/tex].
[tex]\[ \int (8t^3 - 6t^{-2}) \, dt \][/tex]
We'll break this down by integrating each term separately.
1. For the first term [tex]\( 8t^3 \)[/tex]:
[tex]\[ \int 8t^3 \, dt \][/tex]
Using the power rule of integration [tex]\( \int t^n \, dt = \frac{t^{n+1}}{n+1} \)[/tex]:
[tex]\[ \int 8t^3 \, dt = 8 \cdot \frac{t^{3+1}}{3+1} = 8 \cdot \frac{t^4}{4} = 2t^4 \][/tex]
2. For the second term [tex]\( -6t^{-2} \)[/tex]:
[tex]\[ \int -6t^{-2} \, dt \][/tex]
Again using the power rule:
[tex]\[ \int -6t^{-2} \, dt = -6 \cdot \frac{t^{-2+1}}{-2+1} = -6 \cdot \frac{t^{-1}}{-1} = 6t^{-1} = \frac{6}{t} \][/tex]
Summing these results, we get:
[tex]\[ \int (8t^3 - 6t^{-2}) \, dt = 2t^4 + \frac{6}{t} + C \][/tex]
So, the general indefinite integral is:
[tex]\[ 2t^4 + \frac{6}{t} + C \][/tex]
### Part 2: Definite Integral
Now, we need to evaluate the definite integral of the function [tex]\( 8t^3 - 6t^{-2} \)[/tex] from [tex]\( t = 2 \)[/tex] to [tex]\( t = 6 \)[/tex]:
[tex]\[ \int_2^6 (8t^3 - 6t^{-2}) \, dt \][/tex]
We use the antiderivative we found previously and evaluate it at the upper and lower bounds, then take the difference.
Using the antiderivative [tex]\( 2t^4 + \frac{6}{t} \)[/tex]:
1. Evaluate at [tex]\( t = 6 \)[/tex]:
[tex]\[ 2(6)^4 + \frac{6}{6} = 2 \cdot 1296 + 1 = 2592 + 1 = 2593 \][/tex]
2. Evaluate at [tex]\( t = 2 \)[/tex]:
[tex]\[ 2(2)^4 + \frac{6}{2} = 2 \cdot 16 + 3 = 32 + 3 = 35 \][/tex]
Now, subtract the value at the lower bound from the value at the upper bound:
[tex]\[ 2593 - 35 = 2558 \][/tex]
So, the definite integral is:
[tex]\[ \int_2^6 (8t^3 - 6t^{-2}) \, dt = 2558 \][/tex]
### Summary
- The general indefinite integral of [tex]\( 8t^3 - 6t^{-2} \)[/tex] is:
[tex]\[ 2t^4 + \frac{6}{t} + C \][/tex]
- The value of the definite integral of [tex]\( 8t^3 - 6t^{-2} \)[/tex] from [tex]\( t = 2 \)[/tex] to [tex]\( t = 6 \)[/tex] is:
[tex]\[ 2558 \][/tex]
### Part 1: General Indefinite Integral
We need to find the general indefinite integral of the function [tex]\( 8t^3 - 6t^{-2} \)[/tex].
[tex]\[ \int (8t^3 - 6t^{-2}) \, dt \][/tex]
We'll break this down by integrating each term separately.
1. For the first term [tex]\( 8t^3 \)[/tex]:
[tex]\[ \int 8t^3 \, dt \][/tex]
Using the power rule of integration [tex]\( \int t^n \, dt = \frac{t^{n+1}}{n+1} \)[/tex]:
[tex]\[ \int 8t^3 \, dt = 8 \cdot \frac{t^{3+1}}{3+1} = 8 \cdot \frac{t^4}{4} = 2t^4 \][/tex]
2. For the second term [tex]\( -6t^{-2} \)[/tex]:
[tex]\[ \int -6t^{-2} \, dt \][/tex]
Again using the power rule:
[tex]\[ \int -6t^{-2} \, dt = -6 \cdot \frac{t^{-2+1}}{-2+1} = -6 \cdot \frac{t^{-1}}{-1} = 6t^{-1} = \frac{6}{t} \][/tex]
Summing these results, we get:
[tex]\[ \int (8t^3 - 6t^{-2}) \, dt = 2t^4 + \frac{6}{t} + C \][/tex]
So, the general indefinite integral is:
[tex]\[ 2t^4 + \frac{6}{t} + C \][/tex]
### Part 2: Definite Integral
Now, we need to evaluate the definite integral of the function [tex]\( 8t^3 - 6t^{-2} \)[/tex] from [tex]\( t = 2 \)[/tex] to [tex]\( t = 6 \)[/tex]:
[tex]\[ \int_2^6 (8t^3 - 6t^{-2}) \, dt \][/tex]
We use the antiderivative we found previously and evaluate it at the upper and lower bounds, then take the difference.
Using the antiderivative [tex]\( 2t^4 + \frac{6}{t} \)[/tex]:
1. Evaluate at [tex]\( t = 6 \)[/tex]:
[tex]\[ 2(6)^4 + \frac{6}{6} = 2 \cdot 1296 + 1 = 2592 + 1 = 2593 \][/tex]
2. Evaluate at [tex]\( t = 2 \)[/tex]:
[tex]\[ 2(2)^4 + \frac{6}{2} = 2 \cdot 16 + 3 = 32 + 3 = 35 \][/tex]
Now, subtract the value at the lower bound from the value at the upper bound:
[tex]\[ 2593 - 35 = 2558 \][/tex]
So, the definite integral is:
[tex]\[ \int_2^6 (8t^3 - 6t^{-2}) \, dt = 2558 \][/tex]
### Summary
- The general indefinite integral of [tex]\( 8t^3 - 6t^{-2} \)[/tex] is:
[tex]\[ 2t^4 + \frac{6}{t} + C \][/tex]
- The value of the definite integral of [tex]\( 8t^3 - 6t^{-2} \)[/tex] from [tex]\( t = 2 \)[/tex] to [tex]\( t = 6 \)[/tex] is:
[tex]\[ 2558 \][/tex]
Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! Thank you for visiting IDNLearn.com. We’re here to provide dependable answers, so visit us again soon.