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Sagot :
To find the density of the metal, we need to follow these steps:
1. Determine the volume of the metal:
- First, we find the initial volume of water in the graduated cylinder, which is 25.0 mL.
- After the metal is added, the water level rises to 33.0 mL.
- The volume of the metal is therefore the difference between the final and initial water levels:
[tex]\[ \text{Volume of the metal} = \text{Final water level} - \text{Initial water level} = 33.0\ \text{mL} - 25.0\ \text{mL} = 8.0\ \text{mL} \][/tex]
2. Calculate the density of the metal:
- Density is defined as mass per unit volume. The mass of the metal is given as 48.0 grams and we have already found the volume to be 8.0 mL.
- Using the formula for density:
[tex]\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \][/tex]
- Substituting the known values:
[tex]\[ \text{Density} = \frac{48.0\ \text{g}}{8.0\ \text{mL}} = 6.0\ \text{g/mL} \][/tex]
Therefore, the density of the metal is [tex]\(6.0\ \text{g/mL}\)[/tex].
The correct answer is:
[tex]\[ 6.0\ \text{g/mL} \][/tex]
1. Determine the volume of the metal:
- First, we find the initial volume of water in the graduated cylinder, which is 25.0 mL.
- After the metal is added, the water level rises to 33.0 mL.
- The volume of the metal is therefore the difference between the final and initial water levels:
[tex]\[ \text{Volume of the metal} = \text{Final water level} - \text{Initial water level} = 33.0\ \text{mL} - 25.0\ \text{mL} = 8.0\ \text{mL} \][/tex]
2. Calculate the density of the metal:
- Density is defined as mass per unit volume. The mass of the metal is given as 48.0 grams and we have already found the volume to be 8.0 mL.
- Using the formula for density:
[tex]\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \][/tex]
- Substituting the known values:
[tex]\[ \text{Density} = \frac{48.0\ \text{g}}{8.0\ \text{mL}} = 6.0\ \text{g/mL} \][/tex]
Therefore, the density of the metal is [tex]\(6.0\ \text{g/mL}\)[/tex].
The correct answer is:
[tex]\[ 6.0\ \text{g/mL} \][/tex]
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