To solve this problem, we need to identify which two lakes have crocodiles and alligators in the same proportional relationship. This means that the ratio of crocodiles to alligators in these two lakes should be equivalent.
Let’s calculate the ratio of crocodiles to alligators for each lake:
1. Lake A:
- Number of Crocodiles = 4
- Number of Alligators = 5
- Ratio = [tex]\( \frac{4}{5} = 0.8 \)[/tex]
2. Lake B:
- Number of Crocodiles = 21
- Number of Alligators = 35
- Ratio = [tex]\( \frac{21}{35} = 0.6 \)[/tex]
3. Lake C:
- Number of Crocodiles = 3
- Number of Alligators = 9
- Ratio = [tex]\( \frac{3}{9} = 0.333 \)[/tex]
4. Lake D:
- Number of Crocodiles = 6
- Number of Alligators = 16
- Ratio = [tex]\( \frac{6}{16} = 0.375 \)[/tex]
5. Lake E:
- Number of Crocodiles = 24
- Number of Alligators = 30
- Ratio = [tex]\( \frac{24}{30} = 0.8 \)[/tex]
Next, we compare these ratios to determine which two lakes have the same ratio:
- Lake A and Lake E both have a ratio of 0.8.
- Lake B has a ratio of 0.6.
- Lake C has a ratio of 0.333.
- Lake D has a ratio of 0.375.
From this comparison, we see that:
- Lake A and Lake E have the same ratio.
Thus, the two lakes with the same proportion of crocodiles to alligators are Lake A and Lake E.
So, the correct answer is:
C. lake A and lake E
