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\begin{tabular}{|l|l|l|l|}
\hline \multicolumn{1}{|c|}{ Chemical Name } & \multicolumn{1}{|c|}{ Chemical Formula } & \multicolumn{1}{|c|}{ Chemical Name } & \multicolumn{1}{c|}{ Chemical Formula } \\
\hline acetate & [tex]$C_2H_3O_2^{-}$[/tex] & nitrite & [tex]$NO_2^{-}$[/tex] \\
\hline carbonate & [tex]$CO_3^{2-}$[/tex] & ammonium & [tex]$NH_4^{+}$[/tex] \\
\hline hypocarbonite & [tex]$CO^{2-}$[/tex] & cyanide & [tex]$CN^{-}$[/tex] \\
\hline \begin{tabular}{l}
hydrogen carbonate \\
(bicarbonate)
\end{tabular} & [tex]$HCO_3^{-}$[/tex] & hydroxide & [tex]$OH^{-}$[/tex] \\
\hline chlorite & [tex]$ClO_2^{-}$[/tex] & peroxide & [tex]$O_2^{2-}$[/tex] \\
\hline hypochlorite & [tex]$ClO^{-}$[/tex] & phosphate & [tex]$PO_4^{3-}$[/tex] \\
\hline chlorate & [tex]$ClO_3^{-}$[/tex] & hydrogen phosphate & [tex]$HPO_4^{2-}$[/tex] \\
\hline perchlorate & [tex]$ClO_4^{-}$[/tex] & dihydrogen phosphate & [tex]$H_2PO_4^{-}$[/tex] \\
\hline
\end{tabular}

Type the correct answer in each box.

Manganese(III) oxide is a transition metal compound.

The oxidation state of manganese in this compound is [tex]$\square$[/tex] and the chemical formula of the compound is [tex]$\square$[/tex] [tex]$\square$[/tex] [tex]$\square$[/tex].

Sagot :

GinnyAnsweridn
To determine the oxidation state of manganese and the chemical formula of Manganese(III) oxide, let's break down the information provided and understand it step-by-step.

1. Manganese(III) oxide:
- The "(III)" indicates that manganese has an oxidation state of +3.
- The "-oxide" means the compound contains oxygen, which typically has an oxidation state of -2 in oxides.

2. Balancing the charges:
- Manganese has an oxidation state of +3.
- Oxygen has an oxidation state of -2.

3. Finding the right proportions:
- To balance the charges in the compound, consider that each manganese ion contributes +3 charge and each oxygen ion contributes -2 charge.
- We need to find a combination where the total positive charge equals the total negative charge.

4. Determining the chemical formula:
- Suppose we have [tex]\(x\)[/tex] atoms of manganese (Mn) and [tex]\(y\)[/tex] atoms of oxygen (O).
- The charge contributed by manganese is [tex]\(3x\)[/tex] (since each Mn is +3).
- The charge contributed by oxygen is [tex]\(-2y\)[/tex] (since each O is -2).

To balance the charges:
[tex]\[ 3x = 2y \][/tex]
Simplifying this equation, we need to find the smallest whole number ratio:
[tex]\[ x = 2 \quad \text{and} \quad y = 3 \][/tex]

5. Resulting chemical formula:
- Therefore, the chemical formula that balances the charges is [tex]\( \text{Mn}_2\text{O}_3 \)[/tex].

Conclusion:
- The oxidation state of manganese in Manganese(III) oxide is +3.
- The chemical formula of Manganese(III) oxide is Mn₂O₃.

So, the answers are:
- The oxidation state of manganese in this compound is [tex]\(3\)[/tex].
- The chemical formula of the compound is [tex]\(Mn_2O_3\)[/tex].
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