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Question 4, 4.1, 4.1

HW Score: 42.86%

Part 1 of 4

Suppose that the quantity supplied [tex]\( S \)[/tex] and quantity demanded [tex]\( D \)[/tex] of T-shirts at a concert are given by the following functions, where [tex]\( p \)[/tex] is the price:

[tex]\[
\begin{array}{l}
S(p) = -250 + 45p \\
D(p) = 1000 - 80p
\end{array}
\][/tex]

Answer parts (a) through (c).

(a) Find the equilibrium price for the T-shirts at this concert.

The equilibrium price is \$[tex]\(\square\)[/tex] (Round to the nearest dollar as needed.)


Sagot :

To find the equilibrium price for the T-shirts at the concert, we need to determine the price at which the quantity supplied [tex]\( S \)[/tex] is equal to the quantity demanded [tex]\( D \)[/tex]. This involves solving for the price [tex]\( p \)[/tex] in the equations given by the supply and demand functions:

[tex]\[ S(p) = -250 + 45p \][/tex]
[tex]\[ D(p) = 1000 - 80p \][/tex]

The equilibrium price occurs where the quantity supplied equals the quantity demanded:

[tex]\[ -250 + 45p = 1000 - 80p \][/tex]

To solve for [tex]\( p \)[/tex], first combine like terms and solve the equation step-by-step:

1. Add [tex]\( 80p \)[/tex] to both sides to isolate [tex]\( p \)[/tex]:

[tex]\[ -250 + 45p + 80p = 1000 \][/tex]

[tex]\[ -250 + 125p = 1000 \][/tex]

2. Add 250 to both sides to further isolate the term involving [tex]\( p \)[/tex]:

[tex]\[ 125p = 1000 + 250 \][/tex]

[tex]\[ 125p = 1250 \][/tex]

3. Finally, divide both sides by 125 to solve for [tex]\( p \)[/tex]:

[tex]\[ p = \frac{1250}{125} \][/tex]

[tex]\[ p = 10 \][/tex]

Thus, the equilibrium price is [tex]\(\$10\)[/tex].

Therefore, the equilibrium price is:

[tex]\[ \$ \boxed{10} \][/tex]

(rounded to the nearest dollar, as required).